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3 years ago

Who’s is the definition of physical fitness?

Physics

2 answers:

jeyben [28]3 years ago

6 0

The ability to perform aspects of sports .

Zigmanuir [339]3 years ago

4 0

Physical fitness is your ability to carry out tasks without undue fatigue. Learn about the components of physical fitness: cardio respiratory endurance, muscle strength, muscle endurance, flexibility and body composition and why they are important.

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________ is a thermodynamic function that increases with the number of energetically equivalent ways to arrange components of a

ss7ja [257]

Answer:

entropy

Explanation:

5 0

3 years ago

For a point charge, how does the potential vary with distance from the point charge, r?

mr_godi [17]

For a point charge, how does the potential vary with distance from the point charge, r?

a constant

b. r.

c. 1/r.

d. $1/r^2$ .

e. $r^2$ .

Answer:

The correct option is C

Explanation:

Generally for a point charge the electric potential is mathematically represented as

$V = \frac{k Q }{r }$

Here we can deduce that the electric potential varies inversely with the distance i.e

$V \ \alpha \ \frac{1}{r}$

3 0

3 years ago

A proton is released from rest at the positive plate of a parallelplatecapacitor. It crosses the capacitor and reaches the negat

Triss [41]

Answer:

2.1406 × $10^6$ m/sec

Explanation:

we know that energy is always conserved

so from the law of energy conservation

$qV=\frac{1}{2}mv^2$

here V is the potential difference

we know that mass of proton = 1.67× $10^{-27}$ kg

we have given speed =50000m/sec

so potential difference $V=\frac{\frac{1}{2}\times 1.67\times 10^{-27}50000^2}{1.6\times 10^{-19}}=13.045$

now mass of electron =9.11× $10^{-31}$

so for electron

$\frac{1}{2}\times 9.11\times 10^{-31}v^2=1.6\times 10^{-19}\times 13.045=2.1406\times 10^6 m/sec$

so the velocity of electron will be 2.1406× $10^6$ m/sec

4 0

3 years ago

2. A car is traveling with a velocity of 40 m/s and has a mass of 1,120 kg. Calculate the kinetic energy.

klasskru [66]

Answer:

896,000 J

Explanation:

m = 1,120 kg

v = 40 m/s

kinetic energy = mv^2/2 = 1,120 * 40^2/2= 896,000 J

7 0

3 years ago

The usual electrosurgical apparatus contains an oscillator that produces a high-frequency current of frequencies above 500,000 c

AURORKA [14]

Answer:

B Electrocoagulation.

It is a process that involves the use of high frequency current to cause coagulation usually of protiens in tissues and also the destruction of abnormal tissues making use of the heat generated by the electric current. This tissue could be a tumor or some other kind of lesion.

Explanation:

The passage of electric current through the electrode (second electrode that has been sterilized) in contact with the tissue causes the molecules within them to vibrate. This leads to a sharp increase in the temperature of the tissue due to the heat generated by the electric current. This is what causes the coagulation of the proteins within the tissue and also burns the tissue thereby effectively destroying it.

Electrocoagulation also called electrocautery, electrofulguration, and fulguration.

8 0

3 years ago