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Inessa [10]
3 years ago
12

A long electric cable is suspended above the earth and carries a current of 345 A parallel to the surface of the earth. The eart

h’s magnetic field has a value of 5.6 × 10−5 T and makes an angle of 88.2 ◦ with respect to the cable. What is the magnitude of the force f exerted on a cable of length 46.9 m due to the earth’s magnetic field? Answer in units of N
Physics
1 answer:
jok3333 [9.3K]3 years ago
7 0

Answer:

0.906 N

Explanation:

Formula for magnetic force acting on current carrying cable:

F = IBLsin(\theta)

Where I = 345A is the current in the wire, B = 5.6*10^{-5} T is the magnetic magnitude generated by Earth. L = 46.9 m is the cable length. \theta = 88.2^o is the angle between vector B and cable direction.

F = 345*5.6*10^{-5}*46.9*sin(88.2^o)

F = 0.906 N

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The energy (such as light and heat) released by the Sun is produced by nuclear reactions in the core of the Sun, which convert h
Yanka [14]

Answer:

<em>the mass of one helium nucleus should be</em> <em>less than the mass of four hydrogen nuclei.</em>

Explanation:

Deep inside the core of the Sun, enough protons can collide into each other with enough speed that they stick together to form a helium nucleus and generate a tremendous amount of energy at the same time. This process is called nuclear fusion.

The mass-to-energy conversion is described by Einstein's famous equation:

E = mc2, or, in words, energy equals mass times the square of the velocity of light. Because the velocity of light is a very large number, this equation says that lots of energy can be gained from using up a modest amount of mass.

Photons In the proton-proton chain reaction, hydrogen nuclei are converted to helium nuclei through a number of intermediates. The reactions produce high-energy photons (gamma rays) that move through the "radiative layer" surrounding the core. This layer takes up 60 percent of the radius of the Sun. It takes a million years for energy to get through this layer into the "convective layer", because the photons are constantly intercepted, absorbed and re-emitted. In the core, the helium nuclei make up 62% of the mass (the rest is still hydrogen). The radiative and convective layers have about 72% hydrogen, 26% helium, and 2% heavier elements (by mass). The energy produced by fusion is then transported to the solar surface and emitted as light or ejected as high-energy particles.

3 0
3 years ago
What frequency is received by a stationary mouse just before being dispatched by a hawk flying at it at 24.7 m/s and emitting a
Montano1993 [528]

Answer:

   f' = 3665.51 Hz

Explanation:

given,

speed of the hawk = 24.7 m/s

frequency of screech emitted by the hawk = 3400 Hz

speed of sound = 331 m/s

By Doppler's effect

f' = (\dfrac{v}{v-v_s}})f

f' is the frequency received by the mouse

v is the speed of the sound

v_s is the speed of the hawk

now,

f' = \dfrac{341}{341-24.7}}\times 3400

   f' = 1.078 x 3400

   f' = 3665.51 Hz

The frequency received by the stationary mouse is equal to 3665.51 Hz

6 0
3 years ago
A rock hits a window and stops in 0.15 seconds. The net force on the rock is 58N during the collision. What is the magnitude of
nlexa [21]

Answer:

The change in momentum is  \Delta p =   0.7 \ kg\cdot m \cdot s^{-1}

Explanation:

From the question we are told that

    The time taken for the stone to stop is \Delta  t = 0.15 \ seconds

    The net force on the rock is  F =  58 \ N

   

The impulse of the rock can be mathematically represented as

     I  =  F * \Delta t

Substituting values

     I  =  58 * 0.15

    I  =  0.7\  kg * m  * s^{-1}

Now impulse is defined as  the rate at which momentum change

   Hence the change in momentum \Delta p  of the rock is equal to the impulse of the rock

 So  

       \Delta p =  I  =  0.7 \ kg\cdot m \cdot s^{-1}

7 0
4 years ago
A small water pump is used in an irrigation system. The pump takes water in from a river at 10oC, 100 kPa at a rate of 5 kg/s. T
sergij07 [2.7K]

Answer:

0.98kW

Explanation:

The conservation of energy is given by the following equation,

\Delta U = Q-W

\dot{m}(h_1+\frac{1}{2}V_1^2+gz_1)-\dot{W} = \dot{m}(h_2+\frac{1}{2}V_2^2+gz_)

Where

\dot{m} = Mass flow

h_1 =Specific Enthalpy (IN)

h_2 = Specific Enthalpy (OUT)

g = Gravity

z_{1,2} = Heigth state (In, OUT)

V_{1,2} =Velocity (In, Out)

Our values are given by,

T_i = 10\°C

P_1 = 100kPa

\dot{m} = 5kg/s

z_2 = 20m

For this problem we know that as pressure, temperature as velocity remains constant, then

h_1 = h_2

V_1 = V_2

Then we have that our equation now is,

\dot{m}(gz_1) = \dot{m}(gz_2)+\dot{W}

\dot{W} = \frac{(5)(9.81)(0-20)}{1000}

\dot{W} = -0.98kW

8 0
3 years ago
The ossicles (the three tiny bones in the middle ear) are responsible for __________.
Feliz [49]

Answer:

D.amplifying sound vibrations from the eardrum

this is correct

3 0
3 years ago
Read 2 more answers
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