For an investigation, a student measures the speed of a cart as it rolls down a ramp. The student then records data in the table
shown above. Which of these best explains the student’s data?
A.
The speed of the cart decreases as the cart rolls down the ramp because of friction between the cart and the ramp.
B.
The speed of the cart increases as the cart rolls down the ramp because the force acting on the cart is greater than the force of gravity.
C.
The speed of the cart increases as the cart rolls down the ramp because the forces acting on the cart are unbalanced.
D.
The speed of the cart decreases as the cart rolls down the ramp because the forces acting on the cart are balanced.
A.
The speed of the cart decreases as the cart rolls down the ramp because of friction between the cart and the ramp.
B.
The speed of the cart increases as the cart rolls down the ramp because the force acting on the cart is greater than the force of gravity.
C.
The speed of the cart increases as the cart rolls down the ramp because the forces acting on the cart are unbalanced.
D.
The speed of the cart decreases as the cart rolls down the ramp because the forces acting on the cart are balanced.
2 answers:
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Answer:
The International Space Station move at 7.22 km/s.
Explanation:
Orbital speed of satellite is given by , where G is gravitational constant, M is mass of Earth and r is the distance to satellite from centre of Earth.
r = R + h = 6350 + 1400 = 7750 km = 7.75 x 10⁶ m
G = 6.673 x 10⁻¹¹ Nm²/kg²
M = 5.98 x 10²⁴ kg
Substituting
The International Space Station move at 7.22 km/s.
Answer:
15.75 m
Explanation:
First, let's look at the top brick by itself. In order for it not to tip over the bottom brick, its center of gravity must be right at the edge of the bottom brick. So the edge of the top brick must be 10.5 m from the edge of the bottom brick.
Now let's look at both bricks as a combined mass. We know the total length of this combined brick is 10.5 m + 21 m = 31.5 m. And we know that for it to not tip over the edge of the surface, its center of gravity must be at the edge. So the edge of the combined brick must be 31.5 m / 2 = 15.75 m from the edge of the surface.
