Answer:
The current deer population is 240.
Step-by-step explanation:
The expression given models a exponential decay follows:

For every year that passes since the beginning of the count the population is 0.978 of the year prior. Assuming that the count starts at this year, then "n" is equal to 0, applying this value of n to the formula gives us:

The current deer population is 240.
Answer:
Equation:(4 2/5)/2/5=? ; estimate: a
little more than 10 magazines; answer:
11 magazines in the stack.
Step-by-step explanation:
(2,3)??? Maybe? I really don’t know
Answer: 0.0775
Step-by-step explanation:
Given : Mean : 
Standard deviation : 
Sample size : 
Since its normal distribution , then the formula to calculate the z-score is given by :-

For x= 28.2 hours

For x= 30 hours

The P- value = 

Hence, the probabiliy that the average time spent stydying for the sampe was between 28.2 and 30 hours = 0.0775