Why is the study of technological history important?
2 answers:
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Answer:
The specific volume is reduced in 80 per cent due to isothermal compression.
Specific enthalpy remains constant.
Explanation:
Let suppose that neon behaves ideally, the equation of state for ideal gases is:
Where:
- Pressure, measured in kilopascals.
- Volume, measured in cubic meters.
- Molar quantity, measured in kilomoles,
- Temperature, measured in kelvins.
- Ideal gas constant, measured in
.
On the other hand, the molar quantity () and specific volume (
), measured in cubic meter per kilogram, are defined as:
and
Where:
- Mass of neon, measured in kilograms.
- Molar mass of neon, measured in kilograms per kilomoles.
After replacing in the equation of state, the resulting expression is therefore simplified in term of specific volume:
Since the neon is compressed isothermally, the following relation is constructed herein:
Where:
,
- Initial and final pressure, measured in kilopascals.
,
- Initial and final specific volume, measured in cubic meters per kilogram.
The change in specific volume is given by the following expression:
Given that and
, the change in specific volume is:
The specific volume is reduced in 80 per cent due to isothermal compression.
Under the ideal gas supposition, specific enthalpy is only function of temperature, as neon experiments an isothermal process, temperature remains constant and, hence, there is no change in specific enthalpy.
Specific enthalpy remains constant.
Complete Question:
Show the bias polarities and depletion regions of an npn BJT in the normal active, saturation, and cutoff modes of operation. Draw the three sketches one below the other to (qualitatively) reflect the depletion widths for these biases, and the relative emitter, base, and collector doping.
Consider a BJT with a base transport factor of 1.0 and an emitter injection efficiency of 0.5.
Calculate roughly by what factor would doubling the base width of a BJT would increase, decrease, or leave unchanged the emitter injection efficiency and base transport factor? Repeat for the case of emitter doping increased 5 × =. Explain with key equations, and assume other BJT parameters remain unchanged!
Answer & Explanation:
[Find the attachments]
Step 1 :
Emitter and base, collector, and base are forward biased then BJT is in saturation region. Emitter and base is forward biased and base and collector in reverse biased then BJT is in active region.
Emitter and base, collector and base are reverse biased then BJT in cut off region.
Three sketches one below the other is shown in Figure 1.
[find the figure in attachment]
Step 2:
Value of base widths of saturation, active and cut off operated BJT are value of Base width of saturated region operated BJT is less than base width in active region operated BJT. Value of base width of active region operated BJT is less than base width in cut off region operated BJT.
Saturation region operated base width of BJT is < Active region operated base width of BJT is < Cut off region operated base width of BJT.
[For Steps 3 4 5 6 and 7 find attachments]
