For simple integer factors as this one has, you want to find two values for the quadratic in the form ax^2+bx+c. Let the two values be j and k. These two values must satisfy two conditions.
jk=ac=10 and j+k=b=11, so j and k must be 1 and 10.
Now replace bx with jx and kx...
2x^2+x+10x+5 now factor 1st and 2nd pair of terms.
x(2x+1)+5(2x+1)
(x+5)(2x+1)
Answer:
0.1 for each case
Step-by-step explanation:
Because Jordan's teacher randomly calls on students and Jordan has 10% chance of being called on any given day, the probability that on the first day Jordan is called on is 0.1 Besides, the probability remains constant on any given day, so, the probability that on the 2nd day Jordan is called on is 0.1 and for the 5th day is the same 0.1 Probability is always a number between 0 and 1.
Answer:
y=2x-13
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-7-(-1))/(3-6)
m=(-7+1)/-3
m=-6/-3
m=2
y-y1=m(x-x1)
y-(-1)=2(x-6)
y+1=2(x-6)
y=2x-12-1
y=2x-13
