Question

Find four consecutive integers whose sum is 114.

Answer 1

If n is the first of these integers, then the other three are n + 1, n + 2, and n + 3. Then

n + (n + 1) + (n + 2) + (n + 3) = 114

4n + 6 = 114

4n = 108

n = 27

So the four numbers are 27, 28, 29, and 30.