Answer:
6/25 km in 1 min; or 0.24 km/min
Step-by-step explanation:
The info about Angel is not necessary.
Jayden runs 3 laps in 5 mins
Each lap is 2/5 km, so Jayden runs 3 x (2/5 km) in 5 min = 6/5 km in 5 min.
Distance = rate x time
6/5 km = rate (5 min)
We want to isolate r (rate), so divide both sides by 5 min
6/5 km ÷ 5 min = r
6/5 km (1/5 min) = r
6/25 km/min = r (notice how the units worked out correctly to km/min)
So, Jayden runs 6/25 km in 1 min.
Answer:
(8,10) is not a solution
Step-by-step explanation:
Cuz it’s not on both inequality shaded part but just one of them and also when we substitute one is true and the other one is false
2x + y _< 8
2(8) + 10 _< 8
18 + 10 _< 8
28 _< 8 false
X + y _> 4
8 + 10 -> 4
18 _> 4 true
The 40 ml solution is said to be created from 10 ml and 30
ml solutions. In mixture problems, we equate the final mixture to its
compositions given the concentration for each. A 10 ml has 20% acid and the 30 ml has C
(unknown). We can write the total liters for 10 ml as 10(.2) and 30(c) for the
30 ml. when two solutions were added, it should be equal to 40ml with 32% acid.
Therefore, it should be written as 10(.2) + 30(c) = 40(.32). The answer is A
F(19)= (3/(19+2)) - sqrt(19-3)
= (3/21) - sqrt(16)
= (1/7) - 4
= (1/7) - (28/7)
= -27/7
= - 3 6/7
