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Novosadov [1.4K]
3 years ago
11

Consider the reaction 3Fe2O3(s) + H2(g)2Fe3O4(s) + H2O(g) Using standard thermodynamic data at 298K, calculate the entropy chang

e for the surroundings when 1.68 moles of Fe2O3(s) react at standard conditions. S°surroundings = J/K An error has been detected in your answer. Check
Chemistry
1 answer:
balandron [24]3 years ago
5 0

Answer:

the entropy change for the surroundings when 1.68 moles of Fe2O3(s) react at standard conditions = 49.73 J/K.

Explanation:

3Fe2O3(s) + H2(g)-----------2Fe3O4(s) + H2O(g)

∆S°rxn = n x sum of ∆S° products - n x sum of ∆S° reactants

∆S°rxn = [2x∆S°Fe3O4(s) + ∆S°H2O(g)] - [3x∆S°Fe2O3(s) + ∆S°H2(g)]

∆S°rxn = [(2x146.44)+(188.72)] - [(3x87.40)+(130.59)] J/K

∆S°rxn = (481.6 - 392.79) J/K =88.81J/K.

For 3 moles of Fe2O3 react, ∆S° =88.81 J/K,

then for 1.68 moles Fe2O3 react, ∆S° = (1.68 mol x 88.81 J/K)/(3 mol) = 49.73 J/K the entropy change for the surroundings when 1.68 moles of Fe2O3(s) react at standard conditions.

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Explanation: Hoped this helped! :)

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When light energy excites electrons in photosystem II, where do the electrons to replace them come from?
Artyom0805 [142]
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4 years ago
State, in terms of electrons, why the radius of Na+ ion in the table salt is smaller than the radius of a Na atom.
Anastaziya [24]

Answer:

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• A sodium atom has one more electron shell than a sodium ion.

• A Na+ ion is formed when a Na atom loses an electron

3 0
2 years ago
You have a 100 ml stock solution of 100 mg/ml ampicillin in deionized water. You want to make 30 ml of 25 mg/ml ampicillin in de
Georgia [21]

Explanation:

Volume of the stock solution is V_{1} = ?

Initial concentration of ampicillin is M_{1} = 100 mg/ml

Final volume (V_{2}) = 30 ml

Final concentration of  ampicillin (M_{2}) = 25 mg/ml

Therefore, calculate the volume of given stock as follows.

              M_{1} \times V_{1} = M_{2} \times V_{2}

Now, putting the given values into the above formula as follows.

            M_{1} \times V_{1} = M_{2} \times V_{2}

            100 mg/ml \times V_{1} = 25 g/ml \times 30 ml    

                   V_{1} = 7.5 ml

Now, we will calculate the volume of water added into it as follows.

            Volume of water added = V_{2} - V_{1}

                                                  = 30 ml - 7.5 ml

                                                  = 22.5 ml

Thus, we can conclude that required solution is 22.5 ml of deionized water.

3 0
3 years ago
What is the mass of an 80 mL aliquot of a solution with a density of 5.80<br> g/mL?
Setler [38]

Answer:

The answer is

<h2>464 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of solution = 80 mL

density = 5.80 g/mL

The mass is

mass = 80 × 5.8

We have the final answer as

<h3>464 g</h3>

Hope this helps you

4 0
3 years ago
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