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Charra [1.4K]
3 years ago
6

During one researcher's experiment, the total mass of the gas-generating solid and entire assembly was 52.1487g before the react

ion and 52.1098g after the reaction. If the number of moles of gas generated was calculated to be 8.854 x 10-4 mol, what is the molar mass of the gas?
Chemistry
1 answer:
irinina [24]3 years ago
7 0

Answer:

43.93 g/mol

Explanation:

The mass of the gas before reaction = 52.1487 g

The mass of the gas after reaction = 52.1098 g

Mass of gas generated = 0.0389 g

Moles of the gas = 8.854\times 10^{-4}\ moles

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Molar\ mass = \frac{Mass\ taken}{Moles}

Molar\ mass= \frac{0.0389\ g}{8.854\times 10^{-4}\ moles}

Molar mass of the gas = 43.93 g/mol

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Answer:

1) The value of Kc:

C. remains the same.

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Hello,

In this case, by means of the Le Chatelier's principle which is based on the shift a chemical reaction could have under some modifications, we have:

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ln(K)=\frac{\Delta _RG}{RT}

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Thus, the lower the concentration of ammonia, the higher Qc, making Qc>Kc.

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8 0
4 years ago
Read 2 more answers
Anybody know the answer to this
eduard

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2 years ago
The dissolution of 0.200 l of sulfur dioxide at 19 °c and 745 mmhg in water yields 500.0 ml of aqueous sulfurous acid. The solut
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Answer:

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Explanation:

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Pressure = 745 mm Hg

Also, P (mm Hg) = P (atm) / 760

Pressure = 745 / 760 = 0.9803 atm

Temperature = 19 °C

The conversion of T( °C) to T(K) is shown below:

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Using ideal gas equation as:

PV=nRT

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P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

0.9803 atm × 0.200 L = n × 0.0821 L.atm/K.mol × 292.15 K  

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Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.016348}{0.0134}\ M

Molarity=1.22\ M

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the process of changing one form of energy into another

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