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Lapatulllka [165]
3 years ago
11

Convert 43 F to Kevin. (Remember units on your answer and SHOW YOUR WORK)

Chemistry
1 answer:
gavmur [86]3 years ago
4 0

Answer:

279.26K

Explanation:

T(k) = (43 + 459.67)×5/9

502.67 × 5/9

279.26 K

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2 years ago
Is plastic is substance, homogenous or heterogineous mixture
yarga [219]

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Plastic is compound not the substance because substance is consist of mixture . It may be homogeneous due to plastic beads in molten state are in equal ratio

Explanation:

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3 years ago
When given any reaction how do I figure out the products and then balance it?
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AB(aq)+C  >A +CB(aq)
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3 years ago
A 1.000 mL sample of acetone, a common solvent sometimes used as a paint remover, was placed in a small bottle whose mass was kn
ra1l [238]

Answer:

See explanation

Explanation:

Precision means the reputability of measurement and accuracy means how close a measurement is to the actual value. To get the measured mass of the acetone we need to substract the mass of the bottle from the measured mass of bottle and acetone.

The mass of the bottle is 38.0015g

⇒The mass of acetone in bottle 1= 0.7783g

⇒Mass of acetone in bottle 2= 0.7780g

⇒Mass of acetone in bottle3= 0.7786g

The measured value is near to each other. ⇒ the measurements are <u>precise</u>.

To check the <u>accuracy</u> we can compare the average value to the actual mass of the acetone.

Average of the acetone measurement is (0.7783+0.7780+0.7786)/3 = 0.7783g

The percentage of difference of the average measurement to the actual mass is = {(actual value-measured value)/actual value}x100%

={(0.7791-0.7783)/0.7791}x100%

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So we can see the difference is very small ⇒ the measurement is accurate.

7 0
3 years ago
The following are electronegativity. What value should be where the M is?0.981.57M2.553.043.443.98No data
ipn [44]

Answer 2.04

Explanation

Electronegativity decreases down the group and increases across the period in the periodic table.

In the period two of the periodic table,we have the following values for electronegativities with respect to its elements.

Li...........0.98

Be.........1.57

B..........2.04

C.........2.55

N..........3.04

O...........3.44

F...........3.98

Ne........n.a

The value that should be where M is is 2.04

6 0
1 year ago
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