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spayn [35]
3 years ago
10

Explain why molecules of water were attracted to the negatively charged plastic tube while molecules of cyclohexane were not. Dr

aw a picture showing the interaction of the water molecules with the plastic tube.

Chemistry
1 answer:
mihalych1998 [28]3 years ago
5 0

Answer:

See attached

Explanation:

Structural geometry is the key to understanding particle-particle interactions on a physical levels. Suggest a review of molecular geometry and states of matter for a more in depth understanding. Doc                                                

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Materials:
shusha [124]

Answer:

Nice experiment

Explanation:

8 0
3 years ago
1. What elements are carbohydrates generally composed of?
Llana [10]
The correct answer is  hydrogen<span>, and </span>oxygen<span>. </span>
4 0
3 years ago
Read 2 more answers
If the pOH of a nitric acid (HNO3) solution is measured as 11, what is the concentration of HNO3 solution? Choose one
miss Akunina [59]
PH + pOH = 14

pH
= 14 - pOH
= 14 - 11
= 3

pH = 3
- lg [H+] = 3
[H+]
= 0.001
= [HNO3]
= 1 x 10-3 M
8 0
2 years ago
A gas mixture contains helium (He ), argon (Ar) , neon (Ne ), Xenon ( Xe), and krypton (Kr) gases. The total pressure of the gas
MA_775_DIABLO [31]

Answer:

0.488atm = Pressure Kr

Explanation:

The total pressure in a mixture of gases could be defined as the sum of the partial pressures of a mixture. For the mixture of gases in the problem:

Total pressure = Pressure He + Pressure Ar + Pressure Ne + Pressure Xe + Pressure Kr

Converting the total pressure to atm:

1252.5mm Hg * (1atm / 760 mmHg) = 1.648 atm

Replacing:

1.648atm = 0.32atm + 0.21atm + 0.44atm + 0.19atm + Pressure Kr

<h3>0.488atm = Pressure Kr</h3>
5 0
3 years ago
Find the pH of a 0.350 M aqueous benzoic acid solution. For benzoic add. Ka = 6.5 x 10^-5.
slava [35]

Answer:

correct option is (a)

The solution would be using this: C6H5COOH = H+ + C6H5COO Ka = 6.5 x 10^-5 = (H+)(C6H5COO-) over

(C6H5COOH)

Let X = moles per liter (H+) and also = moles per liter (C6H5COO-)

Ka = 6.5 x 10^-5 = (X)(X) over .350 molar = acid solution 6.5 x 10^-5 = X^2 over .350

X^2 = 6.5 x 10^-5 times .350 which = 2.275 x 10^-5

x = V2.275 x 10^-5

X = 1.5083 x 10^-5 moles per liter H+

pH = -log(H+) = -log 1.5083 x 10^-5 which

= 4.6215

7 0
3 years ago
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