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Lina20 [59]
2 years ago
9

What is the equation of the line that is

Mathematics
1 answer:
Lena [83]2 years ago
7 0

Answer:

y = 1x - 3

Step-by-step explanation:

Note that the given line has slope +1.

Any line parallel to this line must also have slope +1.

Apply the slope-intercept form y = mx + b:

Inserting -3 for y, 0 for x and 1 for m, we get the y-intercept

-3 = 1(0) + b, which tells us that b = -3 and that the desired equation is

y = 1x - 3

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bearhunter [10]

Answer:

3+37=40

3/40×1200=90kg

37÷40×1200=1110kg

Step-by-step explanation:

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352 . If you multiply 16 by 22 it will give u an answer of 352
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At what point on the curve y = 19 2x is the tangent line perpendicular to the line 20x 4y = 1?
Gennadij [26K]

The points are; (7/2, -1/2).

<h3>What is the given point?</h3>

Now the tangent line is given as;20x 4y = 1. When we rewrite it in the slope intercept form, we have the equation as; y = 1 - 20x/4 or y = 1/4 - 5x.

Then to obtain the slope of the curve we have; y = 19 - 2x

dy/dx = 2

Using the relation;

m1m2 = -1

m2 = -1/2

Hence;

y = 1/4 - 5(-1/2)

y = 1/4 + 5/2

y = 7/2

Thus the points are; (7/2, -1/2)

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2 years ago
the length of a rectangle is 12 inches more than it's width what is it's width of the rectangle if the perimeter is 42 inches​
dimaraw [331]

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3.5

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Find the first five terms of the sequence given the following recursive formula:
forsale [732]

Answer:

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-3,-7,11,-29,69

Step-by-step explanation:

The recursive definition of the sequence is

a_1=-3,, a_2=-7 and a_n=a_{n-2}-2a_{n-1}.

When n=3, we obtain;

a_3=a_{3-2}-2a_{3-1}.

\implies a_3=a_{1}-2a_{2}.

\implies a_3=-3-2(-7).

\implies a_3=11.

When n=4

\implies a_4=a_{2}-2a_{3}.

\implies a_4=-7-2(11)=-29.

When n=5

\implies a_5=a_{3}-2a_{4}.

\implies a_4=11-2(-29)=69.

Therefore the first five terms are;

-3,-7,11,-29,69

5 0
3 years ago
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