When a 20 kg explosive detonates and sends a 5 kilogram piece traveling to the right at 105 m/s
1 answer:
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Answer:
correct answer is option A (Yes, becuase acceleration depends on the rate of change of velocity and not the value of velocity itself.)
Explanation:
we know that from first equation of motion,
v=u+at
0r
............(1)
here,
v-final velocity
u-initial velocity
a-acceleration
t-time
if a body is not moving it means if its initial velocity is zero (u=0) and if after time t it moves with velocity v then its acceleration will be given as
...........(2)
From above equation it is clear that if an object is not moving, it can be accelerating because acceleration depends on rate of change of velocity and not the value of velocity itself.
The magnetic force acting on a charged particle moving perpendicular to the field is:
= qvB
is the magnetic force, q is the particle charge, v is the particle velocity, and B is the magnetic field strength.
The centripetal force acting on a particle moving in a circular path is:
= mv²/r
is the centripetal force, m is the mass, v is the particle velocity, and r is the radius of the circular path.
If the magnetic force is acting as the centripetal force, set equal to
and solve for v:
qvB = mv²/r
v = qBr/m
Due to the work-energy theorem, the work done on the proton by the potential difference V becomes the proton's kinetic energy:
W = KE
W is work, KE is kinetic energy
W = Vq
KE = 0.5mv²
Therefore:
Vq = 0.5mv²
Substitute v = qBr/m and solve for V:
V = 0.5qB²r²/m
Given values:
m = 1.67×10⁻²⁷kg (proton mass)
B = 0.750T
q = 1.60×10⁻¹⁹C (proton charge)
r = 1.84×10⁻²m
Plug in the values and solve for V:
V = (0.5)(1.60×10⁻¹⁹)(0.750)²(1.84×10⁻²)²/1.67×10⁻²⁷
V = 9120V