Answer:
A) determine magnetic fields
For 0 ≤ r ≤ a
Magnetic field = ∅ 
For a ≤ r ≤ b
Magnetic field = ∅ 
For b ≤ r ≤ c
Magnetic field in the region = ∅ ![\frac{I}{2\pi r} [ c^2 - r^2 / c^2-b^2 ]](https://tex.z-dn.net/?f=%5Cfrac%7BI%7D%7B2%5Cpi%20r%7D%20%5B%20c%5E2%20-%20r%5E2%20%2F%20c%5E2-b%5E2%20%5D)
For r ≥ c
magnetic filed in the region = 0
B ) attached below
Explanation:
<u>A) Determine the magnetic field in the following regions</u>
i) For 0 ≤ r ≤ a
Magnetic field = ∅ 
attached below is the detailed solution
ii) For a ≤ r ≤ b
Magnetic field = ∅ 
attached below is the detailed solution
iii) For b ≤ r ≤ c
Magnetic field in the region = ∅ ![\frac{I}{2\pi r} [ c^2 - r^2 / c^2-b^2 ]](https://tex.z-dn.net/?f=%5Cfrac%7BI%7D%7B2%5Cpi%20r%7D%20%5B%20c%5E2%20-%20r%5E2%20%2F%20c%5E2-b%5E2%20%5D)
attached below is the detailed solution
iv) For r ≥ c
magnetic filed in the region = 0 and this is because the net current enclosed in the region = 0
Answer:
Both Technician A and Technician B
Explanation:
In order to gain a better understanding of the solution above let define some terms
Break Accumulator
We can define a break accumulator as storage that that helps generate the required pressure in order for the breaking system to respond faster this accumulator is charged by turning the steering wheel slowly at once from lock to lock now this build the pressure in the accumulator and one way to depressurize is it is by turning the ignition switch ""off""
Now a scan tool is a device that can interface with a car it can also be used to diagnose a car an get the diagnostic information to help in the cars diagnoses and also be used to reprogram a car
<span>6.7 x 10-11....Have a good day with a big fat A+
</span>
It's called an action plan
As long as we could organize what actions that are going to be taken, when, where, and what could we achieve by that action, basically we can use anything as an action plan
Action plan is different from a to - do list because an action plan is goal oriented. As long as the goal already accomplished, we don't necessarily have to follow the remaining steps
Answer:
Option D: 21.8 degrees
Explanation:
In a parallel RL circuit, the current in the resistor R and that in the inductor L are separated among themselves 90 degrees as illustrated in the attached image. In the image the current in the resistor is represented in orange, that of the inductor in blue, and the total current (vector addition of the previous two) is represented in red, forming a certain angle (theta) with respect to the current in the resistor. The output voltage is the same as the input voltage as measured over the resistor R.
Therefore, the phase angle that separated output voltage and total current can be obtained using the fact that tan(phase angle) =
, therefore the angle is the arctangent of 4/10:
degrees.