60 time what equals to 120

A sphere has a radius of 12 inches. A second sphere has a radius of 9 inches. What is the difference of the volumes of the spher

just olya [345]

Answer:

Solution given;

for sphere

radius [r]:12inches

another

radius [R]:9inches

Now

difference in volume of sphere:

volume of sphere of having radius [r-R]

= $\frac{4}{3} πr³$ - $\frac{4}{3} πR³$

= $\frac{4}{3} π$ (12³-9³)

= 1332π cubic inches

The volume of the larger sphere is <u>___1332</u>__π cubic inches greater than the volume of the smaller sphere.

3 0

3 years ago

In college basketball, a shot made from beyond a designated arc radiating about 20 ft from the basket is worth three points ins

denis-greek [22]

Answer:

a) By the Central Limit Theorem, the distribution would be approximately normal, with mean $\mu = 0.45$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497$

b) 4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered surprising, so yes, it would be surprising for him to make only 25 of these shots.

Step-by-step explanation:

To solve this question, we are going to need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions, we have that the mean is $\mu = p$ and the standard deviation is $s = \sqrt{\frac{p(1-p)}{n}}$

In this problem, we have that:

$p = 0.45, n = 100$

a)By the Central Limit Theorem, the distribution would be approximately normal, with mean $\mu = 0.45$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497$

b)This is Z when X = 0.25.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.25 – 0.45}{0.0497}$

$Z = -4.02$

4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered

surprising, so yes, it would be surprising for him to make only 25 of these shots.

3 0

3 years ago

IF THE ODDS AGAINST A PARTICULAR CANDIDATE WINNING AN ELECTION ARE 9

ss7ja [257]

The probability that the candidate will win is P = 0.357

<h3>How to find the probability?</h3>

We know that the odds against the particular candidate are 9 to 5.

The the odds for the candidate are 5 to 9, this means that in 5 cases the candidate will win, and in 9 cases the candidate will lose.

Then the candidate wins in 5 out of 14 cases, then the probability that the particular candidate wins the elections is given by the quotient:

P = 5/14 = 0.357

The probability that the candidate will win is P = 0.357

If you want to learn more about probability:

brainly.com/question/25870256

#SPJ1

5 0

2 years ago

you deposit 1,750 into an interestmemt account that will produce 6.05% annual interest the money was left in the account for 2 y

Ymorist [56]

Answer:

i dont know mabey someone else knows

5 0

3 years ago

The number of patients treated at Dr. Artin’s dentist office each day was recorded for nine days. These are the data: 6, 6, 6, 5

klemol [59]

Answer:

D) 5.6, 6, 6, 1

Step-by-step explanation:

Before we start solving this problem, we need to first rearrange the provided data from smallest to greatest, so we get:

5, 5, 5, 5, 6, 6, 6, 6, 6

now we can find the mean. The mean is nothing but the average of the provided values, so we need to add them and then divide them into the total amount of data:

$mean=\frac{5+5+5+5+6+6+6+6+6}{9}=5.6$

next, in an odd number of data, the median is the middle number when written in order. In this case the middle number (the one in the position 5) is 6, so:

median=6

the mode will tell you what is the value that has the greatest number of occurrencies. This is the number that appears the most on our list.

Mode=6

and the range is the difference between the greatest value and the smallest value:

Range=6-5=1

so the answer is D.

6 0

3 years ago