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3 years ago

60 time what equals to 120

Mathematics

2 answers:

motikmotik3 years ago

8 0

Easy 60×2=120 but another way you can find out is 120÷60=2

skelet666 [1.2K]3 years ago

4 0

2 because 60 times 2 equals 120 or 120 divided by 60 equals 2

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Write the standard form for the scientific notation. please help fast!!!

jarptica [38.1K]

$2.32\cdot10^3=2.32\cdot1,000=2,320\\\\4.2\cdot10^4=4.2\cdot10,000=42,000\\\\4.2\cdot10^{-2}=4.2\cdot0.01=0.042$

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3 years ago

Kent multiplies both sides of the equation below by an expression.

Korolek [52]

The steps below are presented in order to arrive to the value of k of the given equation.
First, multiply both sides of the equation by the variable k since the left-hand side of the equation has it in the denominator. This will be,
(k + 12/ k)(k) = 8(k)

Then, we simplify,
k + 12 = 8k
We then, subtract 8k to both sides of the equation,
k - 8k + 12 = 8k - 8k

Simplifying,
-7k + 12 = 0

Then, subtract 12 from both sides of the equation and divide both sides by -7. This will us the final answer of,
k = 12/7

8 0

3 years ago

Read 2 more answers

The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(

Umnica [9.8K]

Answer:

(a) $A_1$ and $A_2$ are indeed mutually-exclusive.

(b) $\displaystyle P(A_1\; \cap \; B) = \frac{1}{20}$ , whereas $\displaystyle P(A_2\; \cap \; B) = \frac{1}{25}$ .

(d) $\displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}$ , whereas $P(A_1 \; |\; B) = \displaystyle \frac{4}{9}$

Step-by-step explanation:

$P(A_1 \; \cap \; A_2) = 0$ means that it is impossible for events $A_1$ and $A_2$ to happen at the same time. Therefore, event $A_1$ and $A_2$ are mutually-exclusive.

By the definition of conditional probability:

$\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}$ .

Rearrange to obtain:

$\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot P(A_1) = 0.25 \times 0.20 = \frac{1}{20}$ .

Similarly:

$\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot P(A_2) = 0.80 \times 0.05 = \frac{1}{25}$ .

Note that:

$\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}$ .

In other words, $A_1$ and $A_2$ are collectively-exhaustive. Since $A_1$ and $A_2$ are collectively-exhaustive and mutually-exclusive at the same time:

$\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}$ .

By Bayes' Theorem:

$\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}$ .

Similarly:

$\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}$ .

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3 years ago

Simplify the expression (2-5 root 6) times 3 root 2

lys-0071 [83]

Answer:

6(√2 - 5√3).

Step-by-step explanation:

3√2 ( 2 - 5 √6)

= 6√2 - 15√12

= 6√2 - 15√4√3

= 6√2 - 30√3

= 6(√2 - 5√3)

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3 years ago

Shelly got 60 questions correct on her math test.If she got 75% how many questions were on the test?

vekshin1

There were 80 questions on the test.

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3 years ago