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Doss [256]
3 years ago
12

Select the ZEROS of the function below. Choose two answers. (See photo)

Mathematics
1 answer:
ella [17]3 years ago
4 0

x^2 +7x +10

when factored becomes

(x+2) (x+5)

 the zeros are x +2 = 0, x = -2

x +5 = 0 x = -5

zeros are -2 and -5


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How many integers between 360 and 630 are there such that they have odd number of divisors?
Kryger [21]

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Concept to Know: "A number is a perfect square if and only if it has odd number of positive divisors "

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19², 20², 21², 22², 23², 24², and 25² are all the squared values that lies between 360 and 630. There are seven of those squared numbers so the answer is 7.

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PLS HELP ME ASAP FOR 7, 8, and 10!! (MUST SHOW WORK!!) + LOTS OF POINTS!) *GIVE THANKS!!*
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