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Artemon [7]
3 years ago
9

Which expression is equivalent to 6X equals 10 X +20

Mathematics
1 answer:
Andrei [34K]3 years ago
7 0
I think it’s 2(5x +10)
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Amanda uses the equation y = kx to determine how much money (y) she earns after working any number of hours (x). Amanda earned $
kondaur [170]
Given the equation y = kx
Also given that she:
earned $350 after working 40 hours
y = how much earned
x = number of hours 
Plug it in
y = kx
350 = k(40)
divide both sides by 40 to find out how much k is
8.75 = k

k = 8.75 so your answer is A.) 8.75

Hope this helps :)
6 0
3 years ago
Read 2 more answers
Suppose that, in addition to edge capacities, a flow network has vertex capacities. That is each vertex has a limit l./ on how m
storchak [24]

Answer:

See explanation and answer below.

Step-by-step explanation:

The tranformation

For this case we need to construct G' dividing making a division for each vertex v of G into 3 edges that on this case are v_1, v_2 and l(v).

We assume that the edges from the begin are the incoming edges of v_1 and all the outgoing edges from v are outgoing edges from v_2

We need to construct G' = (V', E') with capacity function a' and we need to satisfy the follwoing:

For every v \in V we create 2 vertices v_1, v_2 \in V'

Now we can add a new edge asscoiated to v_1, v_2 \in E' with the condition a' (v_1,v_2) = l(v)

Now for each edges (u,v)\in E we can create the following edge ( u_r, v_1) \in E' and the capacity is given by: a' (u_r, v_1) = a (u,v)

And for this case we can see this:

|V'| = 2|V|, |E'|= |E| +|V|

Now we assume that x is the flow who belongs to G respect vertex capabilities. We can create a flow function x' who belongs to G' with the following steps:

For every edge (u,v) \in G we can assume that x' (u_r ,v_1) = x(u,v)

Then for each vertex u \in V -t and we can define x\(u_1,u_r) = \sum_{v \in V} x(u,v) and x' (t_1,t_2) = \sum_{v \in V} x(v,t)

And after see that the capacity constraint on this case would be satisfied since for every edge in G' on the form (u_r, u_1) we have a corresponding edge in G because:

u \in V -(s,t) we have that:

x' (u_1, u_r) = \sum_{v \in V} x(u,v) \leq l(u) = a' (u_1, u_r)

x' (t_1,t_2) = \sum_{v \in V} x(v,t) \leq (t) = a' (t_1,t_2)

And with this we have the maximization problem solved.  

We assume that we have K vertices using the max scale algorithm.

6 0
3 years ago
Carlos bought an item online for $160 and he was charged $8 fee for shipping. What was the percent of the sale was the shipping
prohojiy [21]
Shipping charge was 5%
6 0
4 years ago
Porfavor no me pasen vinculos solo diganme las preguntas porfa
ollegr [7]

Answer:

I dont speak spanish

Step-by-step explanation:

No espanol No ruso

6 0
3 years ago
Which is a stretch of an exponential decay function?
NNADVOKAT [17]

Answer:

The correct option is 3. The function  is a stretch of an exponential decay function.

Step-by-step explanation:

The general form of an exponential function is

where, a is the initial value and b is the growth factor.

If b<1, then it represents a decay function and if b>1, then it represents a growth function.

Let k be a stretch and compression factor.

If k<1, then it represents vertical compression and if k>1, then it represents vertical stretch.

In third function

Therefore the function  is a stretch of an exponential decay function.

7 0
3 years ago
Read 2 more answers
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