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3 years ago

Please help!!! Is this correct????

Mathematics

1 answer:

ahrayia [7]3 years ago

5 0

Answer:

yes

Step-by-step explanation:

Weight appears to be the independent variable, so will be graphed on the horizontal axis. Cost is the dependent variable, so will be graphed on the vertical axis.

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You buy tomato sauce for $0.37 per ounce. One portion of potato gnocchi requires 2 ounces of tomato sauce. How much does the sau

Novay_Z [31]

Answer:

$0.74 = 74 cents

Step-by-step explanation:

The cost of one ounce of tomato = $0.37

1 portion of potato gnocchi requires 2 ounces of tomato sauce.

To find the cost of one portion of the potato gnocchi, we have to simply find the cost of 2 ounces of tomato sauce.

That is:

Cost = 2 * 0.37 = $0.74

Hence, one portion of potato gnocchi costs $0.74

Since $1 = 100 cents, the cost in cents will be:

0.74 * 100 = 74 cents

6 0

3 years ago

Mrs. Yang bought 5 chickens and 3 ducks for $81. A chicken cost $5 more than a duck.

anygoal [31]

The cost of each duck is $ 7 and cost of each chicken is $ 12.

Step-by-step explanation:

Given,

5 chickens and 3 ducks are bought by $ 81

A chicken costs $ 5 more than a duck.

To find the cost of each duck and cost of each chicken.

Let,

The cost of each duck = x

The cost of each chicken = x+5

According to the problem,

5(x+5)+3x = 81

or, 5x+25+3x = 81

or, 8x = 81-25

or, 8x = 56

or, x = 7

Hence,

The cost of each duck = $ 7

The cost of each chicken = $ 7+5 = $ 12

8 0

4 years ago

Find a number in the closed interval [1/2,3/2] such that the sum of the number and its reciprocal is

sattari [20]

Let's assume that number as x

so,

the sum of the number and its reciprocal is

$S(x)=x+\frac{1}{x}$

Firstly, we will find derivative

$S'(x)=1-\frac{1}{x^2}$

now, we can set it to 0

and then we can solve for x

$S'(x)=1-\frac{1}{x^2}=0$

$x=-1,x=1$

Since, only x=1 lies on [1/2,3/2]

so, we will consider only x=1

now, we can plug end values and x=1 into S

At x=1/2:

we can plug x=1/2

$S(\frac{1}{2})=\frac{1}{2} +\frac{1}{\frac{1}{2}}$

$S(\frac{1}{2})=\frac{1}{2} +2$

$S(\frac{1}{2})=\frac{5}{2}$

At x=1:

we can plug x=1

$S(1)=1 +\frac{1}{1}$

$S(1)=1 +1$

$S(1)=2$

At x=3/2:

we can plug x=3/2

$S(\frac{3}{2})=\frac{3}{2} +\frac{1}{\frac{3}{2}}$

$S(\frac{3}{2})=\frac{3}{2} +\frac{2}{3}$

$S(\frac{3}{2})=\frac{13}{6}$

(a)

Smallest value:

The smallest value among them

$S(1)=2$

So, a number is 1..........Answer

(b)

Largest value:

The largest value among them

$S(\frac{1}{2})=\frac{5}{2}$

So, a number is $\frac{1}{2}$ ........Answer

6 0

4 years ago

The scale on a model railroad train set is 3.5 millimeters to 1 foot. If the length of a model car in the set is 150 millimeters

Vera_Pavlovna [14]

Answer:

The approximate length of the actual car is 43 feet.

Step-by-step explanation:

Given:

The scale on a model railroad train set is 3.5 millimeters to 1 foot. If the length of a model car in the set is 150 millimeters.

Now, to find the approximate length of the actual car.

Let the actual length of the car is $x.$

The length of a model car in the set is 150 millimeters.

As, given the scale on a model railroad train set is 3.5 millimeters to 1 foot.

So, 3.5 millimeters equivalent to 1 foot.

Thus, 150 millimeters to $x$ .

Now, to get the actual length of the car by using cross multiplication method:

$\frac{3.5}{1} =\frac{150}{x}$

By using cross multiplying we get:

$3.5x=150$

Dividing both sides by 3.5 we get:

$x=42.85\ feet.$

The approximate length of the actual car = 43 feet.

Therefore, the approximate length of the actual car is 43 feet.

3 0

3 years ago

Read 2 more answers

Question 5

Stolb23 [73]

Answer:

Step-by-step explanation:

8 0

3 years ago