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Allushta [10]
3 years ago
10

confirm or disprove ernest's work by selecting two different points and applying the slope formula. be sure to identify the poin

ts you chose.

Mathematics
1 answer:
yan [13]3 years ago
8 0

Answer:

Part a) Ernest's calculation was correct

Part b) Ernest's calculation was correct

Step-by-step explanation:

The picture of the question in the attached figure

<u><em>The complete question is</em></u>

Ernest calculated the slope of the graph during the uphill climb to be 10. His work is shown below.

Points: (60.900). (15, 450)

Slope : 900-450/60-15=450/45=10

Part a) Determine whether his calculation was correct or incorrect, and then explain why.

Part b) Confirm or disprove Ernest's work by selecting two different points and applying the slope formula. be sure to identify the points you chose

Part a)

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have the points

A(60,900),B(15,450)

Remember that

m_A_B=m_B_A

step 1

Find m_A_B

substitute in the formula

m_A_B=\frac{450-900}{15-60}\\\\m_A_B=\frac{-450}{-45}=10

step 2

Find m_B_A

substitute in the formula

m_B_A=\frac{900-450}{60-15}\\\\m_B_A=\frac{450}{45}=10

therefore

Ernest's calculation was correct, because m_A_B=m_B_A

Part b) selecting two different points

we take the points

(0,300) and (50,800) -----> see the attached figure

substitute in the formula of slope

m=\frac{800-300}{50-0}

m=\frac{500}{50}

m=10

therefore

Ernest's calculation was correct

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Answer:

La población que se espera para el 2012, es 317,060

Step-by-step explanation:

Si la población tiene un crecimiento relativo del 2%, entonces cada año, la población es un 2% más grande que el año anterior.

Definamos P(t) = población después de t años

Entonces, si al año t = 0 (que corresponde con el año 2000) la población es A

P(0) = A

Un año después, en t = 1, la población incrementa en un 2%

P(1) = A + (2%/100%)*A = A + (0.02)*A = A*(1.02)

Otro año después, en t = 2, la población incrementa un 2% de vuelta.

P(2) = A*(1.02) + (2%/100%)*A(1.02) = A*(1.02) + 0.02*A*(1.02)

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Ya podemos notar un patrón, la población en el año t va a ser:

P(t) = A*(1.02)^t

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Entonces A = 250,000

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Entonces la población que se espera para el 2012 es: 317,060

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