A^2 + b^2 = c^2
the sides are 11, 13, and 25
11^2+13^2=290
25^2 = 625
11^2+13^2<25^2
So, this is an obtuse triangle
Answer:
dhdhrjfidgegehfr fhfn fhc fn dncc c. f byn
Just did a specific one of these; let's do the general case.
The point nearest the origin is (a,b).
The line from the origin through the point is

The line we seek is perpendicular to this one. We swap the coefficients on x and y, negating one, to get the perpendicular family of lines. We set the constant by plugging in the point (a,b):


That's standard form; let's plug in the numbers:


Answer:
No
Step-by-step explanation:
because its not a generally vector-valued function