Total number of balls = 50
Balls numbered as multiple of 10 = 5
Balls with red dot on them = 6
Balls numbered as multiple of 10 and having red dot on them = 1 (i.e. Ball with number 40 on it)
Probability of Ball being numbered as multiple of 10 = P(T) = 5/50 = 1/10
Probability of Ball being marked by the dot = P(D) = 6/50 = 3/25
Probability of Ball being numbered as multiple of 10 and having a red dot on it = P (T ∩ D) = 1/50
The "or" ,"union" of two events can be expressed as:
P(T ∪ D) = P(T) + P(D) - P (T ∩ D)
Using the values, we get:
P(T ∪ D) =
Thus, the probability that the ball is numbered with a multiple of 10 or has a red dot is 1/5 or 0.2
ANSWER:
Let width be x, then length be 2x – 2
Now, Area of rectangle = L × B
- x(2x – 2) = 40
- 2x² – 2x – 40 = 0
- 2(x² – x – 20) = 0
- x² – x – 20
- x² –5x + 4x – 20 = 0
- x(x – 5) + 4(x – 5) = 0
- (x + 4)(x – 5) = 0
- x = – 4; 5
Hence, width can't be negative.
So width = 5in.
And Length = 2 × 5 – 2
So, <u>Correct choice</u> - [D] Length is 8 in, Width is 5 in.
Inequality with OR: We use OR when you have two or more cases that could or not happen at the same time, for example with inequalities when you have an OR you use the union of the sets given by the inequalities. for example if we have the following two inequalities

it will represent the union of the set of numbers that are greater than one with the set of the numbers that are less than zero.
Inequality with AND: We use AND when you need that all the conditions holds at the same time (here is not accepted that only one holds) for example with inequalities when you have AND you need to use the intersection of the sets given by the inequalities. For example:

will represent the intersection of the set of number that are greater than two and less than ten AT THE SAME TIME
Answer:
Procedures:
1.) The GCF of a number is the greatest factor/number that you can divide from all the numbers.
2.) The GCF of an exponent is the least value.
ANSWER: 12a² and 38a⁴b²
GCF = 2a²
Factored Form = 2a²(3+19a²b²)