Your daughter found three pieces of ribbon in all different colors. Their lengths were 10 meters and 9 decimeters, 3 meters and
1 answer:
Answer:
The length of the ribbons in all were 25.3 meters.
Step-by-step explanation:
Given:
Lengths of the three pieces of ribbon were 10 meters and 9 decimeters, 3 meters and 10 decimeters, and finally 10 meters and 4 decimeters.
Now, to find the length of the ribbons in all.
So, by adding the length of all three pieces we get the length of all the ribbons:
.
Now, converting the decimeters into meters = 23 meters + 2.3 meters = 25.3 meters.
(1 decimeter = 0.10 meter)
(23 decimeter = 2.3 meter.)
Therefore, the length of the ribbons in all were 25.3 metres.
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Answer:
The height of the larger traffic signs is 51.96 inches
Step-by-step explanation:
Given that initially, A company makes traffic signs of an equilateral triangle with the perimeter of 144 inches
Now, A company makes similar traffic signs of perimeter 1.25 of original
New perimeter will be 1.25x144=180 inches
Let triangle ABC be a larger triangle with 180inches of the perimeter.
It is given that the triangle is an equilateral triangle,
Therefore, Side AB=BC=AC
The perimeter of a triangle ABC is
AB+BC+AC=180
3AB=180
AB=60 inches
Figure show that triangle ABC and AD is the height of the triangle.
Since, the triangle ABC is an equilateral triangle,
AD is the perpendicular bisector of BC
so that,
BD=DC and Angle ADB=90
In right triangle ADB,
Angle D =90 and Angle B =60
Side BD=60/2=30 inches and AB=60 inches
Using Pythagoras theorem,
AD=51.96 inches
Thus, The height of the larger traffic signs is 51.96 inches
Let's use the variable x to represent the length of the first and second pieces.
If the third piece has twice the length of the first and second, its length is 2x.
If the fourth piece has half the length of the first and second, its length is 0.5*x.
Adding all four pieces and equating to 54 inches, we have:
So the length of each piece is:
12 inches, 12 inches, 24 inches and 6 inches.
Answer: the answer is in the attachment.
