Answer:
The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

93% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).
14a. =
15b. 2/3 is less than 0.667
16c. 3 7/8 is greater than 3.375
17d. 3/8 is less than 1/2
Answer:
y=2/4x+5/2
Step-by-step explanation:
y=mx+b
2-4/-1-3
-2/-4
Slope =2/4
y=2/4x+b
2=2/4(-1)+b
b=5/2
y=2/4x+5/2
The slope would be -5, I will explain if you would like me to
11/7+12/5=55/35+84/35=139/35