$s(x)=x-7\\t(x)=4x^2+3\\\\(t\times s)(x)=t(x)\times s(x)\\\\\text{Substitute:}\\\\(t\times s)(x)=(4x^2+3)(x-7)\\\\\text{use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(t\times s)(x)=(4x^2)(x)+(4x^2)(-7)+(3)(x)+(3)(-7)\\\\=4x^3-28x^2+3x-21$

8 0

3 years ago

5 x 1= 5 5x10=50 5x100=500 5x1000= 5000 What pattern do you notice ?

storchak [24]

Adds a zero each time?

7 0

2 years ago

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Roman solved the equation 5a+2b=10 for a. His steps are shown below. 1. Subtract 2b: 5a+2b-2b=10-2b 2. Multiply by 5: 5a+10-2b W

VladimirAG [237]

Answer:

In step 2, he needed to divide both sides of the equation by 5

Step-by-step explanation:

we have

$5a+2b=10$

Solve for a------> That means isolate the variable "a"

step 1

Subtract 2b to both sides

$5a+2b-2b=10-2b$

$5a=10-2b$

step 2

Divide by 5 both sides

$5a/5=(10-2b)/5$

$a=(10-2b)/5$

3 0

2 years ago

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