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Rudik [331]
4 years ago
15

Using b as the variable for the problem below, solve for b. Submit your answer as an inequality, using "<=" for or ">=" fo

r if necessary. Round to one decimal place. In a team bike race, each biker has to ride exactly 50 miles. If a team must complete 560 miles, at least how many bikers are on each team?
Mathematics
1 answer:
svp [43]4 years ago
7 0
Number of bikers: b

miles ridden by each biker: 50

number of miles ridden by the team: 50b

Condition: 50b ≥ 560

=> b ≥ 560 / 50

=> b ≥ 11,2

Given that b refers no number of persons it has to b an integer and b has to be at least 12

=> b ≥ 12.

If there would be 11 bikers the team only could complete 11*50 = 550 miles, so they cannot complete the required 560 miles.

Answer: b ≥ 12
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4 years ago
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butalik [34]

The answers to each of the given problems are;

1) Sum of two smallest integers  = 23

2) 3x + 6

3) 7.5 m/s²

<h3>How to find the sum of consecutive Integers?</h3>

1) We are told that sum of 4 consecutive integers is increased by 20 and equals 70. Thus, we have;

x + (x + 1) + (x + 2) + (x + 3) + 20 = 70

4x + 26 = 70

4x = 70 - 26

4x = 44

x = 44/4

x = 11

Thus, sum of two smallest integers = 11 + 11 + 1 = 23

2) Let the consecutive odd numbers be;

x, (x + 2) and (x + 4)

Sum of these consecutive odd numbers is;

x + x + 2 + x + 4 = 3x + 6

3) We are given the equation to find the acceleration as;

(v_final)² - (v_initial)² = 2ad

We are given;

v_final = 40 m/s

v_initial = 10 m/s

d = 100 m

Thus;

40² - 10² = 2a(100)

1500 = 200a

a = 1500/200

a = 7.5 m/s²

Read more about sum of integers at; brainly.com/question/17695139

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7 0
1 year ago
Two cars start out together from the same place. they travel in opposite​ directions, with one of them traveling 5 miles per hou
Mashutka [201]
<u>Annotation</u>
General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.


One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5  (first equation)

The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)

Plug the d-v-t relationship to the second equation
d₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262

Plug the v₁ as  (v₂+5) from the first equation
2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.

Find the velocity of the first car, use the first equation
v₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.

Answer
\boxed{\boxed{ v_{1}=68mph} }
\boxed{\boxed{ v_{2}=63mph} }
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