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Nadya [2.5K]
4 years ago
14

A wheel has a diameter of 3.5ft. Approximately how far does it travel if it makes 20 complete revolutions? use 22/7 for pi.

Mathematics
1 answer:
Anna [14]4 years ago
8 0
If the wheel doesn't slip or skid, then every time it makes
a revolution, it travels the circumference of the wheel.

If its diameter is 3.5 ft, then its circumference is  (3.5 pi)

                   = (3.5 ft) x (22/7)  =  77/7 ft  =  11 ft .

In 20 complete revolutions, it travels

                   (20) x (11 ft)  =  220 ft .

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3 years ago
Find the surface area of the cylinder in terms of pi
tia_tia [17]

Answer:

<u>A≈301.44</u>

Step-by-step explanation:

The area of a cylinder is A=2πrh+2πr^2

You first do the first problem of the equation (A=2πrh)

You fill in the radius and height ( A=2π(4)(8) )

You first multiply 4 x 8 = 32. ( A=2π(32) )

Then you multiply 2 x 32 = 64. ( A=π(64) )

Then you multiply π x 64 (using 3.14 for π) = 200.96 m^2

You then do the second part of the equation. (A=2πr^2)

You fill in the radius. (A=2π(4)^2)

Then multiply 4 x 4 = 16 (because it's to the power of 2 [4 times itself twice]) and then multiply it by 2.

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Next you just multiply 32 x π (using 3.14 for π again) = 100.48 m^2.

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200.96 m^2 + 100.48 m^2 = 301.44 m^2

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5 0
3 years ago
Read 2 more answers
Factor of 4-(2a+3b)^2
Anna71 [15]

4-(2a+3b)^2

(2a+3b)^2 :

4a^2+12ab+9b^2

= 4-(4a^3+12ab+9b^2)

=-(4a^2)-(12ab)-(9b^2)

apply minus -  plus rules :

+(-a)=-a

Refine:

=-4-4a^2-12ab-9b^2

<span>hope this helps!</span>
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