In order to answer the question, we simply substitute the value of p and q to the given expression and solve. We do as follows:
<span>P^2q^2+pq–q^3–p^3
</span>0.5^2(-0.5)^2+0.5(-0.5)–(-0.5)^3–(0.5)^3
-3/16 or -0.1875
Hope this answers the question. Have a nice day.
You start with the top number of each fraction and multiply them. So 2x3=6. Next you take the bottom number and multiply. So 3x4=12. That would give you a fraction of 6/12. 6 is half of 12 so 6/12 simplified is equal to 1/2. Hope this helps!
Answer:
x | 0 | 1 | 2 | 3
f(x) | - 7 | 0 | 5 | 8
Step-by-step explanation:
When you reflect a point say across the x-axis, the x-coordinate remains the same, but the y-coordinate is transformed into its opposite (its sign is changed). Therefore if the function f( x ) is reflected across the x - axis, it's new function would be y = - f( x ). This new function is function g, so you can also say y = - g( x ).
Given the following table ...
x | 0 | 1 | 2 | 3
f(x) | 7 | 0 | - 5 | - 8 ... we can keep the x - values constant, but take the opposite of each y - value, or " f( x ). " Doing so the new table should be the following -
x | 0 | 1 | 2 | 3
f(x) | - 7 | 0 | 5 | 8 ... note that 0 remains constant as you can't take it's opposite, it remains zero. Therefore, the function g is represented by the above table.
CA must be in the range [15 - 9, 15 + 9] = [6, 24]
For the line segments to form a triangle the length of CA cannot be less the the difference between the other sides or greater than their sum.
At either extreme the three points A, B and C will be co-linear thus forming a triangle with area of zero
