Given the radius of 50 miles and the line joining the cities at (0, 56) and (58, 0), the transmitter signal can be picked during 59.24 miles of the drive.
<h3>How can the duration of signal reception be found?</h3>
Radius of broadcast of the transmitter = 50 miles
Location of starting point = 56 miles north of the transmitter
Location of destination city = 58 miles east of the transmitter
Therefore we have;
Slope of the line joining the two cities
= 56 ÷ (-58) = -0.966
Which gives the equation of the line as follows;
y = -0.966•x + 56
The equation of the circle is;


1.933156•x^2 - 108.192•x + 636 = 0
Which gives;
Therefore;
When x = 6.67, we have;
- y = -0.966 × 6.67 + 56 = 49.56
When x = 49.29, we have;
- y = -0.966 × 49.29 + 56 = 8.4
The length of the drive, during which the driver can pick the signal, <em>l</em>, is therefore;
l = √((49.56-8.4)^2 + (49.29-6.67)^2) = <u>59.24 miles</u>
- The length of the drive during which the signal is received is 59.24 miles
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Answer:
1. 1/4+1/4=2/4=1/2
2. Yes
3. i don't know
4. Yes
Step-by-step explanation:
1. 1+1=2 therefore you get 2/4 or 1/2
2. 2/3 is the reduced form of 4/6
3. i honestly dont know
4. 3/4 is the reduced form of 9/12
So domain is the number you can use
range is the output your get from inputting the domain given
so from 2≤x≤5
since it is linear, we can be sure that we only need to test the endpoints of the domain to find the endpoints of the range
sub 2 for x
y=2(2)+1
y=4+1
y=5
sub 5 for x
y=2(5)+1
y=10+1
y=11
so range is from 5 to 11
in interval notation: [5,11]
in other notation 5≤y≤11
or
R={y|5≤y≤11}
Answer:
put a picture up
Step-by-step explanation: