Answer:
Step-by-step explanation:
\[2~ sin^2 x+3sin x+1=0\]
\[2sin^2x+2sin x+sin x+1=0\]
2sinx(sin x+1)+1(sin x+1)=0
(sin x+1)(2 sin x+1)=0
either sin x+1=0
sin x=-1=sin 3π/2=sin (2nπ+3π/2)
x=2nπ+3π/2,where n is an integer.
or 2sin x+1=0
sin x=-1/2=-sin π/6=sin (π+π/6),sin (2π-π/6)=sin (2nπ+7π/6),sin (2nπ+11π/6)
x=2nπ+7π/6,2nπ+11π/6,
where n is an integer.
Answer:a,c,d
Step-by-step explanation:
Hello! My name is Chris and I’ll be helping you with this problem.
Date: 9/27/20 Time:
Answer:
x = -1
Explanation:
Step 1: Simplify both sides of the equation.
−2(x+3)=−4(x+1)−4
(−2)(x)+(−2)(3)=(−4)(x)+(−4)(1)+−4(Distribute)
−2x+−6=−4x+−4+−4
−2x−6=(−4x)+(−4+−4)(Combine Like Terms)
−2x−6=−4x+−8
−2x−6=−4x−8
Step 2: Add 4x to both sides.
−2x−6+4x=−4x−8+4x
2x−6=−8
Step 3: Add 6 to both sides.
2x−6+6=−8+6
2x=−2
Step 4: Divide both sides by 2.
2x = -2
/2 /2
x=−1
I hope this helped answer your question! Have a great rest of your day!
Furthermore,
Chris
Answer:
14 & 16
Step-by-step explanation:
30÷2=15
15+15=30, so we can make the conclusion...
14+16=30
Answer:
[-4,9)
Step-by-step explanation:
im like 99% sure this is right bc i just did a problem like this (:
