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3 years ago

What is the value of the discriminant for the quadratic equation 0 = 2x2 + x – 3?

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

7 0

Answer:

Step-by-step explanation:

A = 2, B = 1, C = -3

(1)² - 4(2)(-3)

1 + 24

Goshia [24]3 years ago

4 0

The discriminant is $D=1^2-4(2)(-3)=1+24=\boxed{25}$ .

Hope this helps.

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What is the end behavior of y=-2x^13+25x^8-3 as x approaches infinity?

RUDIKE [14]

Odd degree and negative leading coefient
means it goes from the top left to bottom right
goes infinitely down

as x aproaches infinity, y approaches neagtive infinity

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3 years ago

Solve 5=11-1/3 please i need this

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Answer: look at the point

Step-by-step explanation:

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3 years ago

I will mark brainlyest please help me! Russ compared the heights of the players on two basketball teams, Team 1 and Team 2. He r

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Answer:

Step-by-step explanation:

Median is the dot near the middle of each box. Since median of team one is to the left of that of team 2,

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2 years ago

The sum of the first number cubed and the second number is 500 and the product is a maximum.

soldier1979 [14.2K]

We are given the following information:

the sum of the first number cubed and the second number is 500

their product is a maximum

We are looking for the 2 missing numbers.

To answer this, let's represent the two numbers as x and w.

From the given, we can form the following equation:

$x^3+w=500$

We can then express y as:

$w=500-x^3$

We can express their product as:

$x(500-x^3)=500x-x^4$

To find the maximum value of x, let's solve for the derivative of -x^4 + 500 x.

$\begin{gathered} f(x)=-x^4+500x \\ f^{\prime}(x)=-4x^3+500 \end{gathered}$

Then we solve for the value of x where f'(x) = 0.

$\begin{gathered} -4x^3+500=0 \\ -4x^3=-500 \\ x^3=125 \\ x=5 \end{gathered}$

Then we use x = 5 to solve for the second number, w.

$\begin{gathered} w=500-x^3 \\ w=500-5^3 \\ w=500-125 \\ w=375 \end{gathered}$

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1 year ago

Mhanifa please help these 2 are confusing :( I will mark brainliest

galina1969 [7]

Answer:

The key is to prove that the triangles are congruent, then their corresponding parts are congruent.

Step-by-step explanation:

#5)

It it given that:

Angle CBD is congruent to angle CDB.

Angle BAE is congruent to angle DEA.

Triangle CBD is isosceles because it's base angles are equal. Therefore, segment CB is congruent to segment CD.

Triangle CAE is isosceles because it's base angles are equal. Therefore, segment CA is congruent to segment CE.

CA-CB=BA

CE-CD=DE

segment BD is congruent to segment DB.

Angle ABD is supplementary to angle CBD (180-angle CBD= angle ABD).

Angle EDB is supplementary to angle CDB (1980-angle CDB=angle EDB).

therefore, angle ABD=angle EDB.

Triangles ABD and EDB are congruent because of the Side-angle-side theorem.

Triangles ABD and EDB are congruent, segment AD is congruent to segment EB because corresponding legs of congruent triangles are congruent.

#6)

It is given that:

Angle EBC is congruent to angle ECB

Segment AE is congruent to segment DE.

Triangle BEC is iscsceles because it's base angles are equal. Therefore, segment EB is congruent to segment EC.

AE+EC=AC

DE+EB=DB

segment BC is congruent to segment CB.

Triangle BAC is congruent to triangle CDB because of the side-angle-side theorem.

Segment AD is congruent to segment DC because corresponding legs of congruent triangles are congruent.

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2 years ago

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