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wolverine [178]
3 years ago
11

Find the GCF

Mathematics
1 answer:
Kaylis [27]3 years ago
7 0
Greatest Common Factor. let's go over that. GCF of 6 and 12 would be 6 because 6 goes into 6, 1 times and 6 goes into 12, 2 times. . and it is the largest. so first you see if the lower number can go directly into the higher number. So 28a^2 b^2 c^2, is made of 14abc× 2abc. so you can say 14abc goes into 28a2b2c2, 2abc times. therefore 14abc is the largest factor.
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Containers that have different shapes can not have the same volume.<br> True<br> False
Goshia [24]

Answer:

true

Step-by-step explanation:

rjdkejdkdkekewnensjwkw

6 0
3 years ago
Chris and lisa went shopping and spent a total of $25.50. Lisa spent $13.50 more than chris spent. Hiw much did lisa spend?
baherus [9]

Answer:

12$

Step-by-step explanation:

$25.50-$13.50=$12

5 0
3 years ago
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate α = 8 per hour, so that the number o
Ksenya-84 [330]

Answer:

Step-by-step explanation:

Step1:

We have Suppose small aircraft arrive at a certain airport according to a Poisson process with rate α =8 per hour, so that the number of arrivals during a time period of t hours is a Poisson rv with parameter μ = 8t

Step2:

Let “X” the number of small aircraft that arrive during time t and it follows poisson distribution parameter “”

The probability mass function of poisson distribution is given by

P(X) = , x = 0,1,2,3,...,n.

Where, μ(mean of the poisson distribution)

a).

Given that time period t = 1hr.

Then,μ = 8t

             = 8(1)

             = 8

Now,

The probability that exactly 6 small aircraft arrive during a 1-hour period is given by

P(exactly 6 small aircraft arrive during a 1-hour period) = P(X = 6)

Consider,

P(X = 6) =  

              =  

              =  

              = 0.1219.

Therefore,The probability that exactly 6 small aircraft arrive during a 1-hour period is 0.1219.

1).P(At least 6) = P(X 6)

Consider,

P(X 6) = 1 - P(X5)

                = 1 - {+++++}

                = 1 - (){+++++}

                = 1 - (0.000335){+++++}

                = 1 - (0.000335){1+8+32+85.34+170.67+273.07}

                = 1 - (0.000335){570.08}

                = 1 - 0.1909

                = 0.8090.

Therefore, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8090.

2).P(At least 10) = P(X 10)

Consider,

P(X 10) = 1 - P(X9)

                 = 1 - {+++++

5 0
3 years ago
Factor​ to write an equivalent expression: 5a - 10
Nina [5.8K]
5(a -2)
Djkajksnsj (gay panic because the answer he to be more the 20 characters)
7 0
3 years ago
Two-thirds of the buses in the transit system run on natural gas, and the rest run on diesel. If 738 of the buses run on diesel,
Airida [17]

Answer:

2214 buses

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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