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SVETLANKA909090 [29]
3 years ago
11

A chemistry student needs 50.0 g of methyl acetate for an experiment. By consulting the CRC Handbook of Chemistry and Physics, t

he student discovers that the density of methyl acetate is 0.934 g.cm . Calculate the volume of methyl acetate the student should pour out. Round your answer to 3 significant digits. x s ?
Chemistry
1 answer:
slamgirl [31]3 years ago
3 0

Explanation:

As density is defined as the mass of a substance divided by its volume.

Mathematically,         Density = \frac{mass}{volume}

It is given that mass is 50 g and density is 0.934 g/cm^{3}.

Hence, calculate the volume of methyl acetate as follows.

                     Density = \frac{mass}{volume}

             0.934 g/cm^{3} = \frac{50 g}{volume}

                       Volume = 53.53 cm^{3}

or,                                  = 53.53 ml                (as 1 cm^{3} = 1 mL)

Thus, we can conclude that the volume of methyl acetate the student should pour out is 53.53 ml.

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3 years ago
How many mL of a 1.48 M calcium hydroxide solution are needed to neutralize 36.0 mL of a 1.63 M hydrochloric acid solution
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The volume (in mL) of calcium hydroxide, Ca(OH)₂ needed for the reaction is 19.8 mL

<h3>Balanced equation </h3>

2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O

From the balanced equation above,

  • The mole ratio of the acid, HCl (nA) = 2
  • The mole ratio of the base, Ca(OH)₂ (nB) = 1

<h3>How to determine the volume of Ca(OH)₂ </h3>
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  • Volume of acid, HCl (Va) = 36 mL
  • Molarity of acid, HCl (Ma) = 1.63 M
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MaVa / MbVb = nA / nB

(1.63 × 36) / (1.48 × Vb) = 2

58.68 / (1.48 × Vb) = 2

Cross multiply

2 × 1.48 × Vb = 58.68

2.96 × Vb = 58.68

Divide both side by 2.96

Vb = 58.68 / 2.96

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