The answer is 34.1 mL.
Solution:
Assuming ideal behavior of gases, we can use the universal gas law equation
P1V1/T1 = P2V2/T2
The terms with subscripts of one represent the given initial values while for terms with subscripts of two represent the standard states which is the final condition.
At STP, P2 is 760.0torr and T2 is 0°C or 273.15K. Substituting the values to the ideal gas expression, we can now calculate for the volume V2 of the gas at STP:
(800.0torr * 34.2mL) / 288.15K = (760.0torr * V2) / 273.15K
V2 = (800.0torr * 34.2mL * 273.15K) / (288.15K * 760.0torr)
V2 = 34.1 mL
The answer is N2 + 3H2 yields 2NH3. The oxidation-reduction reaction means that there is electrons transfer during the reaction which means that the valence changed.
Answer:
The molecular formula of the compound :![C_4H_6O_2](https://tex.z-dn.net/?f=C_4H_6O_2)
Explanation:
The empirical formula of the compound =![C_2H_3O](https://tex.z-dn.net/?f=C_2H_3O)
The molecular formula of the compound =![C_{2n}H_{3n}O_n](https://tex.z-dn.net/?f=C_%7B2n%7DH_%7B3n%7DO_n)
The equation used to calculate the valency is :
![n=\frac{\text{molecular mass}}{\text{empirical mass}}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B%5Ctext%7Bmolecular%20mass%7D%7D%7B%5Ctext%7Bempirical%20mass%7D%7D)
We are given:
Mass of molecular formula = 86 g/mol
Mass of empirical formula = 43 g/mol
Putting values in above equation, we get:
![n=\frac{86g/mol}{43g/mol}=2](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B86g%2Fmol%7D%7B43g%2Fmol%7D%3D2)
The molecular formula of the compound :
![C_{2\times 2}H_{3\times 2}O_2=C_4H_6O_2](https://tex.z-dn.net/?f=C_%7B2%5Ctimes%202%7DH_%7B3%5Ctimes%202%7DO_2%3DC_4H_6O_2)
The answer you're looking for is: a wave.
Answer:
C.) No, because the Moon reflects most of the Sun's light rather than
absorbing it
Explanation:
:p