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alex41 [277]
3 years ago
7

If you performed this experiment using mgcl2 as the solute would the molar concentration of mgcl2 that is isotonic to the potato

be higher, the same or lower than the molar concentration of nacl that is isotonic to the potato? explain.
Chemistry
1 answer:
Mama L [17]3 years ago
5 0
The answer to this question would be: lower molar concentration

Osmotic pressure is influenced by the number of ions and the concentration of the molecule in the solution. In NaCl, the molecule will split into 1 Na+ ion and 1 Cl- ion which results in 2 ions per compound. In MgCl2, the compound will split into 1 Mg2+ ion and 2 Cl- ion which results in 3 ions. Therefore, the osmotic pressure of MgCl2 will be 3/2 times of NaCl.
MgCl2 will need less concentration to achieve same osmotic pressure as NaCl. If the MgCl2 solution is isotonic with NaCl, the concentration of MgCl2 would be lower than NaCl
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7 0
2 years ago
What the name of th compound Mg (NO3)2
telo118 [61]
I'm almost certain that it is Magnesium Nitrate
4 0
3 years ago
ASAP PLEASE
marishachu [46]

Answer:

A

Explanation:

the measure of a system's thermal energy per unit temperature that is unavailable for doing useful work.

8 0
3 years ago
Read 2 more answers
The system international (SI) unit for energy is:
Natalija [7]

Question

The system international (SI) unit for energy is:

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3 0
3 years ago
Sodium hydrogen carbonate NaHCO3, also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Ac
olga2289 [7]

Answer:

1.4952 grams of sodium bicarbonate she  would need to ingest to neutralize this much HCl.

Explanation:

Moles (n)=Molarity(M)\times Volume (L)

Moles of hydrochloric acid = n

Volume of hydrochloric acid solution = 200.0 mL = 0.200 L

Molarity of the hydrochloric acid = 0.089 M

n=0.089 M\times 0.200 L=0.0178 mol of HCL

HCl(aq)+NaHCO_3(aq)\rightarrow NaCl(aq)+H_2O(l)+CO_2(g)

According to reaction, 1 mole of HCl is neutralized by 1 mole of sodium bicarbonate.

Then 0.0178 moles of HCl wil be neutralized by :

\frac{1}{1}\times 0.0178 mol=0.0178 mol of sodium bicarbonate

Mass of 0.0178 moles of sodium bicarbonate:

0.0178 mol × 72 g/mol = 1.4952 g

1.4952 grams of sodium bicarbonate she  would need to ingest to neutralize this much HCl.

8 0
3 years ago
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