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3 years ago

Best answer will be tagged brainliest.... no spamming pliz

Chemistry

1 answer:

grin007 [14]3 years ago

5 0

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A. Chloride ions (CI)

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Which statement best explains why magnesium and chlorine combine in a 1:2 ratio?

denpristay [2]

The statement that best explains why magnesium and chlorine combine in a 1:2 ratio is; Magnesium has two valence electrons, and chlorine can accept one electron in its outer shell.

The number of electrons that an atom of an element has in its outermost shell determines the chemical formula of the compounds formed by atoms such elements.

Magnesium is in group 2, as such it has two electrons in its outermost shell while chlorine in group 17 only accepts one electron in its outermost shell. This one electron will give chlorine an inert gas configuration while the loss of two electrons give magnesium an inert gas configuration.

Therefore; The compound MgCl2 is formed in the ratio of 1:2 because Magnesium has two valence electrons, and chlorine can accept one electron in its outer shell.

Learn more: brainly.com/question/11527546

8 0

3 years ago

Would the molecules in a gas have more or less movement than the molecules in a solid ? PLEASE HELP WILL MARK BRAINLY

Sergeeva-Olga [200]

Molecules in a gas will have more movement than molecules in a solid. This is because the molecules in solid matter are packed very tightly together to maintain its shape, whereas with gases they are spaced much further apart and fairly free to move. Hope this helps!

6 0

3 years ago

Write the complete balanced equation for the following reaction: c7h14 o2 yields co2 h2o

Svetach [21]

C7H14 + 10.5 O2 -> 7 CO2 + 7 H2O

Or, if whole numbers must be used:

2 C7H14 + 21 O2 -> 14 CO2 + 7 H2O

3 0

3 years ago

Read 2 more answers

what is the percent yield of titanium (II) oxide if 20.0 grams of titanium (II) sulfide is reacted with water? The actual yield

earnstyle [38]

Answer : The percent yield of titanium (II) oxide is, 142.5 % and the impurities could have caused the percent yield to be so high.

Explanation : Given,

Mass of titanium(II) sulfide = 20.0 g

Molar mass of titanium(II) sulfide = 79.9 g/mole

Molar mass of titanium(II) oxide = 63.9 g/mole

First we have to calculate the moles of titanium(II) sulfide.

$\text{ Moles of titanium(II) sulfide}=\frac{\text{ Mass of titanium(II) sulfide}}{\text{ Molar mass of titanium(II) sulfide}}=\frac{20.0g}{79.9g/mole}=0.2503moles$

Now we have to calculate the moles of titanium(II) oxide.

The balanced chemical reaction is,

$TiS+H_2O\rightarrow TiO+H_2S$

From the reaction, we conclude that

As, 1 mole of titanium(II) sulfide react to give 1 mole of titanium(II) oxide

So, 0.2503 mole of titanium(II) sulfide react to give 0.2503 mole of titanium(II) oxide

Now we have to calculate the mass of titanium(II) oxide.

$\text{ Mass of titanium(II) oxide}=\text{ Moles of titanium(II) oxide}\times \text{ Molar mass of titanium(II) oxide}$

$\text{ Mass of titanium(II) oxide}=(0.2503moles)\times (63.9g/mole)=15.99g$

To calculate the percentage yield of titanium (II) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of titanium (II) oxide = 22.8 g

Theoretical yield of titanium (II) oxide = 15.99 g

Putting values in above equation, we get:

$\%\text{ yield of titanium (II) oxide}=\frac{22.8g}{15.99g}\times 100\\\\\% \text{yield of titanium (II) oxide}=142.5\%$

Hence, the percent yield of titanium (II) oxide is, 142.5 %

If the percent yields is greater than 100% that means the product of the reaction contains impurities which cause its mass to be greater than it actually.

5 0

3 years ago

Each element in the periodic table can be represented by a chemical symbol. Match each element to its chemical symbol.

Andrej [43]

$\qquad\qquad\huge\underline{{\sf Answer}}$

The Correct pair of Element and it's symbol ~

Mercury - Hg

Sodium - Na

Nitrogen - N

Chlorine - Cl

Hydrogen - H

5 0

2 years ago

Best answer will be tagged brainliest.... no spamming pliz​

Best answer will be tagged brainliest.... no spamming pliz