Step-by-step explanation:
This will help okay! I promise you, well I hope .
It's hard to type and hard to read the "inverse tangent" function, as you've seen (above).
So, use "arctan x" instead.
Then the problem becomes: "differentiate cos (arctan x)."
You must apply first the rule for differentiating the cosine function, and next apply the rule for differentiating the arctan function:
(d/dx) cos (arctan x) = - sin (arctan x) * [1/(1+x^2)]
Answer:
Step-by-step explanation:
Put (-6,0) and (0,3) into a table of values
form of the equation: mx+b
x -6 0
y 0 3
3/-6=-0.5 (m)
3=b (the value of y when x=0)
equation: y=0.5x+3
C=7•2=14 this should be right idk