What is the Line that passes through (2,0) and (0,1)
2 answers:
Y = -1/2x + 1
Steps:
1. Find the slope of the given points using the
slope formula:
m= (y2-y1) / (x2-x1)
m= (1-0) / (0-2)
m= - 1/2
2. Take the slope from step 1 and either one of
the points and put into point-slope form:
y-y1 = m(x-x1)
m= - 1/2 point: (2,0)
y-0 = -1/2 (x- 2)
3. Distribute.
y = -1/2x +1
To find the slope you use the equation:
m = (y₂-y₁) ÷ (x₂-x₁)
You plug in the two points into this equation to find m (m is the slope)
m = (1 - 0) ÷ (0 - 2)
m = 1 ÷ (-2)
m = - 1/2
Next you use this equation:
y = mx + b
Because you know m you plug it in.
y = -1/2x + b
Now you need to find b. To do so you plug in either of the points into this equation(you come out with the same answer for b)
y = -1/2x + b
1 = -1/2(0) + b
1 = b
Finally you plug in b and you get your new equation.
y = -1/2x + 1
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