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3 years ago

What is the Line that passes through (2,0) and (0,1)

2 answers:

6 0

Y = -1/2x + 1

Steps:

1. Find the slope of the given points using the
slope formula:
m= (y2-y1) / (x2-x1)

m= (1-0) / (0-2)

m= - 1/2

2. Take the slope from step 1 and either one of
the points and put into point-slope form:
y-y1 = m(x-x1)

m= - 1/2 point: (2,0)

y-0 = -1/2 (x- 2)

3. Distribute.

y = -1/2x +1

zimovet [89]3 years ago

3 0

To find the slope you use the equation:

m = (y₂-y₁) ÷ (x₂-x₁)

You plug in the two points into this equation to find m (m is the slope)

m = (1 - 0) ÷ (0 - 2)

m = 1 ÷ (-2)

m = - 1/2

Next you use this equation:

y = mx + b

Because you know m you plug it in.

y = -1/2x + b

Now you need to find b. To do so you plug in either of the points into this equation(you come out with the same answer for b)

y = -1/2x + b

1 = -1/2(0) + b

1 = b

Finally you plug in b and you get your new equation.

y = -1/2x + 1

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The Cunninghams are moving across the country. Mr. Cunningham leaves 3 hours before Mrs. Cunningham. If he averages 40mph and sh

svp [43]

Recall your d = rt, distance = rate * time

now, if say, by the time they meet, Mr Cunningham has travelled "d" miles, that means Mrs Cunningham must also had travelled "d" miles as well.

However, he left 3 hours earlier, so by the time he travelled "d" miles, and took say "t" hours, for her it took 3 hour less, because she started driving 3 hours later, so, she's been on the road 3 hours less than Mr Cunningham, so by the time they meet, Mrs Cunningham has travelled then "t - 3" hours.

$\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{Mr Cunningham}&d&40&t\\
\textit{Mrs Cunningham}&d&80&t-3
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=40t\\
d=80(t-3)\\
----------\\
\boxed{40t}=80(t-3)
\end{cases}
\\\\\\
\cfrac{40t}{80}=t-3\implies \cfrac{t}{2}=t-3\implies t=2t-6\implies 6=2t-t
\\\\\\
6=t$

5 0

3 years ago

HELP ME PLEASE IM SO LOST

DiKsa [7]

A=10ft because A is 8ft so round that to the nearest ten your answer is 10ft

6 0

3 years ago

Read 2 more answers

What is the answer please.... need help

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

8 0

3 years ago

Which is an important difference between the five themes and the several

Zolol [24]

Answer:

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4 0

3 years ago

Can someone help me simplify this?

ziro4ka [17]

=(14+3i) - (-12-7i) + (6+2i)
=14 + 3i +12 + 7i + 6 + 2i
=32 + 12i

7 0

3 years ago