This is super simple. Begin with cross multiplying
35/x=7/13 becomes (35)*(13)=(7) *(x)
Then multiply my love muffin, you get...
455=7x
divide both sides by 7
65=x
-or-
x=65
hope that helped :)
Answer:
The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h
Step-by-step explanation:
At noon the location of Lan = 300 km north of Makenna
Lan's direction = South
Lan's speed = 60 km/h
Makenna's direction and speed = West at 75 km/h
The distance Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km
The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km
The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km
Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.
By Pythagoras' theorem, we have;
s² = x² + y²
The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61
ds²/dt = dx²/dt + dy²/dt
2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt
2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900
ds/dt = 900/(2×30·√61) ≈ 1.92
The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h
Answer: the equation is
5x^2 -30x - 25
Step-by-step explanation:
A quadratic equation is one in which the highest power of the unknown is 2.
The general form of a quadratic equation is expressed as
ax^2 + bx + c
Where c is a constant and a is the leading coefficient
Assuming we want to write the quadratic equation in x, from the information given, the given roots are 5 and 1 and the leading coefficient is 5. We will just multiply the expression by the leading coefficient.
Therefore, the linear factors of the quadratic will be (x-5) and (x-1)
With the leading coefficient as 5, the equation becomes
5(x-5)(x-1)
= 5(x^2 - x - 5x + 5)
= 5(x^2 - 6x + 5)
= 5x^2 -30x - 25
Mean = 29
Q1 = 19
Q2 = 26
Q3 = 38
IQR = Q3 - Q1 = 38 - 19 = 19
I will assume that the two equations are
1) y = -x^2 +2x + 4 and 2) x +y = 4
subtract 2 from 1 and you get
y -x - y = -x^2 + 2x + 4 - 4
-x = -x^2 +2x
x^2 -x -2x = 0
x^2 - 3x = 0
x(x-3)=0
x=0 and x - 3 =0
x=0 and x = 3
Then y = 4 - x
y = 4 - 0 and y = 4 -3
y = 4 and y =1
Solutions:
Points (0,4) and (3,1)