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klasskru [66]
4 years ago
14

Fghtyuhkjk 1 sdfgdfhgfdgh

Mathematics
2 answers:
Stells [14]4 years ago
7 0

Answer:

drhtfhtfhjfgnhgvnbgnbv

Step-by-step explanation:

gizmo_the_mogwai [7]4 years ago
3 0

Answer:

Step-by-step explanation:

asjdyh aw8ehjw ashhh we8hdajs faedu wendlajsf a

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Cos2a=1-2sin^2a for all values of a.
pickupchik [31]
cos2a= cos^{2} a- sin^{2} a \\ but  \  cos^{2} a + sin^{2} a=1  \\ i.e. \  cos^{2} a=1- sin^{2} a
Therefore,
cos2a=1- sin^{2} a- sin^{2} a \\ =1-2 sin^{2} a
6 0
3 years ago
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What is the area of the triangle?<br><br> /_\<br><br> 18.in<br> 14.in
stepan [7]

Answer:

A=126

Base

18

Height

14

6 0
4 years ago
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The answers are here I just need the work please!!
Flura [38]

the answer 236e

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4 0
4 years ago
Which transformation causes the described change in the graph of the function y = cos x? The transformation results in a horizon
Gala2k [10]
First lets look at our graph of y = cos x
***First picture***

Next lets look at a <span>vertical stretch.
***Second picture***

To vertically stretch y = cos x, we need to multiply cos by a number greater than 1. I am going to use 2.

Standard Form: y = cos x (Red Line)
Vertical Stretch: y = 2 cos x (Blue Line)

Lets look at a vertical shrink
***Third picture***

To create a vertical shrink, you multiply the cos by a number less than 1. I am going to use .5

</span>Standard Form: y = cos x (Red Line)
Vertical Shrink: y = .5 cos x (Green Line)

Now lets look at horizontal stretch.
***Forth picture.***

To create a horizontal stretch, you multiply the x by a value less than 1. I am going to use .5

Standard Form: y = cos x (Red Line)
Vertical Stretch: y = .5 cos x (Orange Line)

Finally, to create a horizontal shrink, you multiply the x by a value greater than 1. I am going to use 2.
***Fifth picture.***

Standard Form: y = cos x (Red Line)
Vertical Shrink: y = 2 cos x (Purple Line)

7 0
4 years ago
Heyyyyyyy? wassupppppppppppp
Lostsunrise [7]

Answer:

Uhhhhhhhhhhhhhhhhhh what? Anyways, I'm <u><em>good</em></u> .-.

6 0
3 years ago
Read 2 more answers
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