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Fynjy0 [20]
2 years ago
15

A walffle cone has a height of 7 inches and a diameter of 3 inches. What is the volume of ice cram that can be contained within

the cone. Use 3.14 for pi. Round to the nearest hundreth
Mathematics
1 answer:
Anna [14]2 years ago
8 0

Answer:

16.49 cubic inches.

Step-by-step explanation:

Given:

A waffle cone has a height of 7 inches and a diameter of 3 inches.

<u>Question asked:</u>

What is the volume of ice cram that can be contained within the cone?

<u>Solution:</u>

First of we will find the radius ;-

Diameter = 3 inches

Radius, r = \frac{Diameter}{2} =\frac{3}{2} =1.5\ inches

As we know:

Volume\ of\ cone=\frac{1}{3} \pi r^{2} h

                          =\frac{1}{3} \times3.14\times1.5\times1.5\times7\\ \\ =\frac{49.455}{3} \\ \\ =16.485

Thus, volume of ice cream will be 16.49 cubic inches.

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Pls help I have no idea what I’m doing
olganol [36]

Answer:

1800

Step-by-step explanation:

61 around to 60 and 29 rounds to 30. so

60 ×30=1800

8 0
3 years ago
Find the measure of angle x in the figure below: A triangle is shown. At the top vertex of the triangle is a horizontal line ali
VLD [36.1K]

Answer:

x=35^\circ

Step-by-step explanation:

From the diagram which I have drawn and attached below:

56^\circ+y+51^\circ=180^\circ$ (Sum of Angles on a Straight Line)\\y=180^\circ-(56^\circ+51^\circ)\\y=73^\circ

Next, in the triangle, the sum of the three interior angles:

y+x+72^\circ=180^\circ\\$Since y=73^\circ\\73^\circ+x+72^\circ=180^\circ\\x=180^\circ-(73^\circ+72^\circ)\\x=35^\circ

The value of angle x is 35 degrees.

7 0
2 years ago
I met a man who said, if you can guess my age, I will pay you one dollar for each year that I have lived . I will also give you
Vladimir79 [104]
He could be 40321 years old.
If you divide 40321 by any odd or even number between 1 and 9, the remainder is 1.

I got this number by doing (2*3*4*5*6*7*8) + 1
4 0
3 years ago
Read 2 more answers
What is the differences in length between the shortest and longest crayons​
anastassius [24]

My answer would be 8.. I may not be correct, but I tried. So, I placed the numbers from least to greatest and split it 1’s and 2’s VS 3’s and 4’s. I just added 1 plus 2 plus 2 and a half plus 2 and a half and got 8. I also added (3+3+3)+3 and a half plus 3

4 0
3 years ago
A professor has recorded exam grades for 10 students in his​ class, but one of the grades is no longer readable. If the mean sco
Nostrana [21]

Answer:

unreadable score = 35

Step-by-step explanation:

We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".

There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":

1) The mean score of ALL exams (including the unreadable one) is 80

so the equation to represent this statement is:

mean of ALL exams = 80

By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:

\frac{R+x}{10} =80

since the mean is the addition of all values divided the total number of exams.

in a similar way we can write what the mean of just the readable exams is:

\frac{R}{9} = 85\\ (notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.

Based on the equation above, we can find what "R" is by multiplying both sides by 9:

\frac{R}{9} = 85\\R=85*9= 765

Therefore we can now use this value of R in the very first equation we created, and solve for "x":

\frac{R+x}{10} =80\\\frac{765+x}{10} =80\\765+x=80*10=800\\765+x=800\\x=800-765=35

4 0
3 years ago
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