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3 years ago

What ion will ACIDS dissociate into in water

Chemistry

1 answer:

Phoenix [80]3 years ago

4 0

Answer:

Hydron

Chemistry

hydrogen

An Arrhenius acid is therefore any substance that ionizes when it dissolves in water to give the H+, or hydrogen, ion. An Arrhenius base is any substance that gives the OH-, or hydroxide, ion when it dissolves in water.

Explanation:

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What is the velosity of a 72.3 kg jogger with a kinetic energy of 1080.0 J?

Svet_ta [14]

Answer: 5.47m/s

Explanation:

Mass = 72.3kg

K.E = 1080.0J

V =?

K.E = 1 /2MV^2

V^2 = 2K.E /M = (2x1080)/72.3

V = sqrt [(2x1080)/72.3]

V = 5.47m/s

7 0

3 years ago

A weighed piece of magnesium ribbon is added to a dried crucible, which is reweighed and heated in air to form the compound MgO.

olga nikolaevna [1]

Answer:

One of the errors for low percentage of magnesium could be because not all the magnesium may have reacted.

Explanation:

During the heating process, if the magnesium have not reacted completely, it can lead to low percentage of magnesium in the oxide formed. The product may still look a bit greyish rather than whitish after the heating process.

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3 years ago

Suppose a 0.025M aqueous solution of sulfuric acid (H2SO4) is prepared. Calculate the equilibrium molarity of SO4−2. You'll find

FromTheMoon [43]

<u>Answer:</u> The concentration of $SO_4^{2-}$ at equilibrium is 0.00608 M

<u>Explanation:</u>

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

$H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)$

0.025 0.025 0.025

Equation for the second dissociation of sulfuric acid:

$HSO_4^-(aq.)\rightarrow H^+(aq.)+SO_4^{2-}(aq.)$

<u>Initial:</u> 0.025 0.025

<u>At eqllm:</u> 0.025-x 0.025+x x

The expression of second equilibrium constant equation follows:

$Ka_2=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}$

We know that:

$Ka_2\text{ for }H_2SO_4=0.01$

Putting values in above equation, we get:

$0.01=\frac{(0.025+x)\times x}{(0.025-x)}\\\\x=-0.0411,0.00608$

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of sulfate ion = x = 0.00608 M

Hence, the concentration of $SO_4^{2-}$ at equilibrium is 0.00608 M

4 0

3 years ago

In general, ionic compounds are hard solids at ambient temperatures but they shatter fairly easily. How do these two properties

lord [1]

Ionic or electrovalent compounds support the theory of ionic bonding because they are compounds composed of charged particles formed when an atom gains or loses electrons.

Electrovalent compounds posses:

High boiling and melting points.
Form crystals.

<h3>What is ionic bonding?</h3>

This is the transfer of valence electrons from metals to non metals to form ionic compounds. It also refers to a chemical bond formed between two ions with opposite charges.

Learn more about ionic compounds:

brainly.com/question/18246121

7 0

2 years ago

Which of the following is an example of convection?

Dovator [93]

Answer:

<h3>C. hot air rising and cooler air failing. </h3>

Explanation:

<h3>Please mark my answer as a brainliest. That is the correct answer. ❤❤❤❤</h3>

3 0

3 years ago