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NeTakaya
2 years ago
10

PLEASE HELP ME ASAP URGENT IM STRESSED AND STUCK

Chemistry
1 answer:
Genrish500 [490]2 years ago
8 0
Is there any more info lol
But from thinking I got A=DH^2*BC
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1. Calculate how many moles of glycine are in a 130.0-g sample of glycine.2. Calculate the percent nitrogen by mass in glycine.
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n=1.732mol

\% N=18.7\%

Explanation:

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In this case, since the molecular formula of glycine is C₂H₅NO₂, we realize that the molar mass is 75.07 g/mol; thus, the moles in 130.0 g of glycine are:

n=130.0g*\frac{1mol}{75.07 g}\\\\ n=1.732mol

Furthermore, we can notice 75.07 grams of glycine contains 14.01 grams of nitrogen; thus, the percent nitrogen turns out:

\% N=\frac{14.01}{75.07}*100\% \\\\\% N=18.7\%

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