All categories

3 years ago

Use the image to answer the question.

Chemistry

2 answers:

Lena [83]3 years ago

7 0

Answer:

1. the process of plants taking in sunlight and creating oxygen

2. outputs are oxygen

3. inputs are sunlight

Explanation:

Aleks04 [339]3 years ago

3 0

1. the process by which green plants and some other organisms use sunlight to synthesise nutrients from carbon dioxide and water.
2. water, carbon dioxide and energy are are inputs .
3. glucose and oxygen are outputs

You might be interested in

If I have 6 moles of a gas at a pressure of 3.4 atm and a volume of 10 liters, what

ch4aika [34]

Answer:

The temperature is 69.05 K.

Explanation:

We have,

Number of moles are 6

Pressure is 3.4 atm and a volume of 10 liters.

It is required to find the temperature. It can be calculated using gas law equation. It says that,

$PV=nRT$

P is pressure

V is volume

n is number of moles

R is gas constant, $R=0.082057\ L-atm/mol-K$

T is temperature

Plugging all the values we get :

$T=\dfrac{PV}{nR}\\\\T=\dfrac{3.4\times 10}{6\times 0.082057}\\\\T=69.05\ K$

So, the temperature is 69.05 K.

8 0

3 years ago

Which is the largest? O 43.32 mL 0 0,0056 L O 0.000076 KL

mel-nik [20]

Answer:

43.32 ML is bigger

3 0

3 years ago

Read 2 more answers

The edge length of the unit cell of KCl (NaCl-like structure, FCC) is 6.28 Å. Assuming anion-cation contact along the cell edge,

Mila [183]

Answer:

1.33 Å

Explanation:

Given that the edge length , a of the KCl which forms the FCC lattice = 6.28 Å

Also,

For the FCC lattice in which the anion-cation contact along the cell edge , the ratio of the radius of the cation to that of anion is 0.731.

Thus,

$\frac {r^+}{r^-}=0.731$ .................1

Also, the sum of the radius of the cation and the anion in FCC is equal to half of the edge length.

Thus,

$r^++r^-=\frac {a}{2}$ ...................2

Given that:

$Cl^-\ (r^-) = 1.82\ \dot{A}$

To find,

$K^+\ (r^+) = ? \dot{A}$

Using 1 and 2 , we get:

$1.731\ r^+=0.731\times \frac {6.28}{2}$

Size of the potassium ion = 1.33 Å

4 0

3 years ago

The pKa of the α‑carboxyl group of serine is 2.21 , and the pKa of its α‑amino group is 9.15 . Calculate the average net charge

sleet_krkn [62]

Answer:

Net charge in serine at pH equal to 8.30 is "0"

Explanation:

At pH > $pK_{a}$ , carboxyl group exists as $-CO_{2}^{-}$ (charged)

At pH < $pK_{a}$ , carboxyl group exists as -COOH (neutral)
At pH > $pK_{a}$ , amino group exists as $-NH_{2}$ (neutral)
At pH < $pK_{a}$ , amino group exists as $-NH_{3}^{+}$ (charged)
So, at pH = 8.30, both carboxyl and amino group exists in charged state.
Net charge in serine at pH equal to 8.30 is "0".
Structure of serine at pH equal to 8.30 has been shown below.

8 0

3 years ago

What is the number of moles in 42 g of NaCl?

olganol [36]

B. 0.72 mol NaCl

http://www.convertunits.com/from/grams+NaCl/to/moles

8 0

3 years ago

Read 2 more answers