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Reika [66]
3 years ago
15

Fertilizer runoff has a negative impact on aquatic ecosystems because _______.

Chemistry
2 answers:
NeX [460]3 years ago
7 0
<span>The answer is a. it causes plants and algae to grow quickly, suffocating organisms in the water. The rapid growth of organisms due to fertilizer runoff leads to a process called eutrophication. When the vegetation dies, the process of decomposition leads to the formation of excessive amounts of carbon dioxide, which in turn suffocates aquatic animals.</span>
swat323 years ago
3 0

A .

. it causes a plants and alged to grow quicklly, suffocating organisums in tkhe water

just took the test

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For each equation given below, enter the number in the space provided to correctly answer the question.
victus00 [196]

Answer:

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Explanation:

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4 0
3 years ago
If I add 2.75 g of CaO to 155 mL of distilled water, what will be the concentration of the solution be?
IRINA_888 [86]
M = m/L
moles of CaO = 2.75g / molar mass
2.75g/ 56.08g = 0.049moles CaO
155mL / 1000 = 0.155 L
M= 0.049moles/0.155L
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7 0
2 years ago
Identify the acids and the bases in the chemical equation ​
agasfer [191]
<h3><u>Answer;</u></h3>

Acids;  HCl and HC5H5N+

Bases; C5H5N and Cl-

<h3><u>Explanation;</u></h3>
  • According to Bronsted-Lowry Theory an acid is a proton or hydrogen ion donor while a base is a proton or a hydrogen ion acceptor.
  • In this case,<u> both HCl and HC5H5N+ are acids</u> as <u>they are donors of hydrogen ions</u>. HCl is an acid to the forward reaction while HC5H5N+ is a acid to the reverse reaction.
  • On the other hand, <u>C5H5N and Cl- are bases</u>, <u>they are acceptors of hydrogen  ions</u>. Cl-  is a base in the reverse reaction while C5H5N is a base in the forward reaction.
8 0
3 years ago
Determine the reducing agent in the following reaction. Explain your answer. 2 Li(s) + Fe(C2H3O2)2(aq) → 2 LiC2H3O2(aq) + Fe(s)
Brilliant_brown [7]

The reducing agent in the reaction 2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s) is lithium (Li).

The general reaction is:

2Li(s) + Fe(CH₃COO)₂(aq) → 2LiCH₃COO(aq) + Fe(s)   (1)

We can write the above reaction in <u>two reactions</u>, one for oxidation and the other for reduction:

  • Oxidation reaction

Li⁰(s) → Li⁺(aq) + e⁻   (2)

  • Reduction reaction

Fe²⁺(aq) + 2e⁻ → Fe⁰(s)    (3)

We can see that Li⁰ is oxidizing to Li⁺ (by <u>losing</u> one electron) in the lithium acetate (<em>reaction 2</em>) and that Fe²⁺ in iron(II) acetate is reducing to Fe⁰ (by <u>gaining</u> two <em>electrons</em>) (<em>reaction 3</em>).  

We must remember that the reducing agent is the one that will be oxidized by <u>reducing another element</u> and that the oxidizing agent is the one that will be reduced by <u>oxidizing another species</u>.

In reaction (1), the<em> reducing agent</em> is <em>Li</em> (it is oxidizing to Li⁺), and the <em>oxidizing agent </em>is<em> Fe(CH₃COO)₂</em> (it is reducing to Fe⁰).  

Therefore, the reducing agent in reaction (1) is lithium (Li).  

 

Learn more here:

  • brainly.com/question/10547418?referrer=searchResults
  • brainly.com/question/14096111?referrer=searchResults

I hope it helps you!

3 0
2 years ago
9. Elements that are characterized by the filling of p orbitals are classified as
Bogdan [553]

Answer:

p block elements

Explanation:

6 0
3 years ago
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