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Korolek [52]
4 years ago
13

HELP These images represent waves. Which wave has the highest frequency?

Physics
2 answers:
Ierofanga [76]4 years ago
7 0

Wave C

because it is the closest or each wave is closer than the others

finlep [7]4 years ago
6 0

hi it is a  because I did process of elimination so plz give me the Brainlist

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PLEASE HELP ASAP!!
Stells [14]

Its B: reduce the amount of energy needed to do the work by putting the work onto something else

3 0
3 years ago
Read 2 more answers
QUESTION 3Plasticity refers to the:A.fact that many academic fields contribute data to the science of development.B.ability of h
Solnce55 [7]

Answer:

B.ability of human traits to be molded during development.

Explanation:

Plasticity:

 1.When pressure is applied then some deformation occurs and to retain this deformation is known as plasticity.

2. It is the capacity of molding

Plasticity refers to the ability of human traits to be molded during development.

So the option B is correct.

B.ability of human traits to be molded during development.

6 0
3 years ago
What is an electric field? How<br> do you calculate the electric<br> field due to a point charge?
Elza [17]
An electric field is an electric property associated with each point in space when charge is present in any form.
7 0
2 years ago
Calculate the power of a light bulb that uses 40J of electricity in 4 seconds.
alexdok [17]

Answer:

power=work done /time

power=40J/4s

power=10wat

7 0
3 years ago
A toy train is pushed forward and released at Xi = 4.0 m with a speed of 2.5 m/s. It rolls at a steady speed for 2.0 s, then one
Fittoniya [83]
I don't think that 4m has anything to do with the problem. anyway. here. A___________________B_______C where A is the point that the train was released. B is where the wheel started to stick C is where it stopped From A to B, v=2.5m/s, it takes 2s to go A to B so t=2 AB= v*t = 2.5 * 2 = 5m The train comes to a stop 7.7 m from the point at which it was released so AC=7.7m then BC= AC-AB = 7.7-5 = 2.7m now consider BC v^2=u^2+2as where u is initial speed, in this case is 2.5m/s v is final speed, train stop at C so final speed=0, so v=0 a is acceleration s is displacement, which is BC=2.7m substitute all the number into equation, we have 0^2 = 2.5^2 + 2*a*2.7 0 = 6.25 + 5.4a a = -6.25/5.4 = -1.157 so acceleration is -1.157m/(s^2)
8 0
3 years ago
Read 2 more answers
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