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Answer:
4.433 kW
Explanation:
Suppose the flow rate is the same at the inlet and outlet at 57 m3/hr.
Since 1 hour = 60 minutes = 3600 seconds we can calculate the flowrate in m3/s
As we are neglecting loss from friction and elevations changed, the power delivered by the pump is the product of the change in pressure and the flow rate
Answer:
vₓ = 20 m/s, v_{y} = -15 m / s
Explanation:
This is a conservation of moment problem, since it is a vector quantity we can work each axis independently
The system is formed by the two drones, so the forces during the crash are internal and the moment is conserved
X axis
Initial moment. Before the crash
p₀ = m₁ v₀ₓ + m₂ v₀ₓ
Final moment. After the crash
p_{fx} = (m₁ + m₂) vₓ
p₀ₓ =
m₁ v₀ₓ + m₂ v₀ₓ = (m₁ + m₂) vₓ
vₓ = (m₁ + m₂) v₀ₓ / (m₁ + m₂)
vₓ = v₀ₓ = 20 m/s
Y Axis
Initial
p_{oy} = m₁ v_{oy}
Final
p_{fy} = (m₁ + m₂) v_{y}
p_{oy} = p_{fy}
the drom rises and when it falls it has the same speed because there is no friction v_{oy} = -60 m/s
m₁ = (m₁ + m₂) v_{y}
v_{y} = m₁ / (m₁ + m₂) v_{oy}
v_{y} = 1/4 60
v_{y} = -15 m / s
Vertical speed is down
Answer:
The magnitude of the frictional force between the car and the track is 367.763 N.
Explanation:
The roller coster has an initial gravitational potential energy, which is partially dissipated by friction and final gravitational potential energy is less. According to the Principle of Energy Conservation and Work-Energy Theorem, the motion of roller coster is represented by the following expression:
Where:
,
- Initial and final gravitational potential energy, measured in joules.
- Dissipated work due to friction, measured in joules.
Gravitational potential energy is described by the following formula:
Where:
- Mass, measured in kilograms.
- Gravitational constant, measured in meters per square second.
- Height with respect to reference point, measured in meters.
In addition, dissipated work due to friction is:
Where:
- Friction force, measured in newtons.
- Travelled distance, measured in meters.
Now, the energy equation is expanded and frictional force is cleared:
If ,
,
,
and
, then:
The magnitude of the frictional force between the car and the track is 367.763 N.