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Rom4ik [11]
3 years ago
14

What are used to draw plane shapes

Physics
1 answer:
babunello [35]3 years ago
7 0
Stencils, ruler, penciles thing like that.
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What is the purpose of the Climate Friendly Farming Project?
blsea [12.9K]
<span>The Climate Friendly Farming Project was designed to provide funding for long term research into the sustainability and adaptability of agricultural systems(wheat, vegetables, and dairy systems) as increasing greenhouse gases propagate and decline the efficiency of current agricultural practice.</span>
4 0
3 years ago
A car engine applies a force of 65,000 N, how much work is done by the engine as it pushed a car a distance of 75 m?
kupik [55]

Answer:

workdone = force \times distance \\  = 65000 \times 75 \\  = 4,875,000 \: J

3 0
2 years ago
A person sitting in a chair with wheels stands up, causing the chair to roll backward across the floor. How would you describe t
OleMash [197]
Scenes the chair wheels are up the person is rolling backwards and if the wheels were down then the person would go forwards
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3 0
3 years ago
A straight segment of a current-carrying wire has a current element IL where I = 2.70 A and L = 3.20 cm i + 4.30 cm j. The segme
myrzilka [38]

The component of the force in negative z-direction is -0.144 N.

The given parameters;

  • <em>current in the wire, I = 2.7 A</em>
  • <em>length of the wire, L = (3.2 i + 4.3j) cm</em>
  • <em>magnetic filed, B = 1.24 i</em>

The force on the segment of the wire is calculated as follows;

F = ILBsin(\theta)

where;

  • <em>θ is the angle wire and magnetic field</em>

<em />

The force on the wire segment will be perpendicular in negative z-direction (applying right hand rule), so there won't be any x and y component of the force.

The angle between the wire and the magnetic field is calculated as follows;

\theta = tan^{-1} (\frac{y}{x} )\\\\\theta = tan^{-1} (\frac{4.3}{3.2} )\\\\\theta = 53.3 \ ^0

The magnitude of the wire length is calculated as follows;

|l | = \sqrt{3.2^2 + 4.3^2} = 5.36 \ cm = 0.0536 \ m

The component of the force in negative z-direction is calculated as;

F_z = -ILB sin(\theta)\\\\F_z = -2.7 \times 0.0536 \times 1.24 \times  sin(53.3)\\\\F_z = -0.144 \ N

Thus, the component of the force in negative z-direction is -0.144 N.

Learn more here:brainly.com/question/22719779

6 0
2 years ago
The mass of Object 2 is double the mass of Object 5. The mass of Object 4 is half of the mass of Object 5 and the mass of Object
SVETLANKA909090 [29]
This is a great problem if you like getting tied up in knots
and making smoke come out of your brain.

I found that it makes the problem a lot easier if I give the objects some
numbers. I'm going to say that the mass of Object 5 is 20 clods.

Let the mass of Mass of Object 5 be 20 clods .

Then . . .

-- The mass of Object 2 is double the mass of Object 5 = 40 clods.

-- The mass of Object 4 is half of the mass of Object 5 = 10 clods.
and
-- the mass of Object 3 is half of the mass of Object 4 = 5 clods.

So now, here are the masses:

Object #1 . . . . . unknown
Object #2 . . . . . 40 clods
Object #3 . . . . . 5 clods
Object #4 . . . . . 10 clods
Object #5 . . . . . 20 clods .

Now let's check out the statements, and see how they stack up:

Choice-A:
Object 3 and Object 5 exert the same gravitational force on Object 1.
Can't be.
Objects #3 and #5 have different masses, so they can't both
exert the same force on the same mass.

Choice-B.
Object 2 and Object 4 exert the same gravitational force on Object 1.
Can't be.
Objects #2 and #4 have different masses, so they can't both
exert the same force on the same mass.

Choice-C.
The gravitational force between Object 1 and Object 2 is greater than
the gravitational force between Object 1 and Object 4.
Yes ! Yay !
Object-2 has more mass than Object-4 has, so it must exert more force on
ANYTHING than Object-4 does, (as long as the distances are the same).

Choice-D.
The gravitational force between Object 1 and Object 3 is greater than the gravitational force between Object 1 and Object 5.
Can't be.
Object-3 has less mass than Object-5 has, so it must exert less force on
ANYTHING than Object-4 does, (as long as the distances are the same).

Conclusion:
If the DISTANCE is the same for all the tests, then Choice-C is
the only one that can be true.
8 0
3 years ago
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