Considering the ballon to be spherical
It's volume is given by 4/3(π r^3) by differentiating volume with respect to time we get rate of change of volume hence,
4πr^2(dr/dt)=600÷60=10
Substituting r=30cm
4π(30)*(30)(dr/dt)=10
dr/dt=rate of increase in bullion's radius=1/(360π)cm/s
Answer:
D. 8
Step-by-step explanation:
y varies jointly as x and z
y = k(xz)
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Find k, the constant of variation
y = 12 when x = -2 and z=3
12 = k(-2 * 3)
12 = k(-6)
k = -2
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find y when x is 4 and z is -1
using k = -2
y = -2(4 * -1)
y = -2(-4)
y = 8
Answer: C
Step-by-step explanation:
1.2x-10=0.2x+14
subtract 0.2x
1.0x-10=14
add 10
x=24
Area = PI x r^2
area = 3.14 x 6^2
area = 3.14 x 36
area = 113.04 square yards
round the answer if needed.
The length could be 23 or more because 23 x 5 = 115 so it could be also
23≥x
