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lozanna [386]
4 years ago
7

A block of lead has dimensions of 4.50 cm by 5.20 cm by

Physics
1 answer:
nordsb [41]4 years ago
5 0

Answer:

0.01132 g/mm^{3}

Explanation:

Density, \rho=\frac {m}{v}

Where m is the mass of the object and v is the volume of the same object

Given the dimensions, we can make them in mm hence 45 mm by 52 mm by 60 mm

Volume=45*52*60= 140400 mm^{3}

Density, \rho=\frac {1590}{140400}=0.011324786 g/mm^{3}\approx 0.01132 g/mm^{3}

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What is the overall charge of the wall?
NNADVOKAT [17]

Answer:

The overall charge on the wall is zero.

Explanation:

Because the atoms making the wall are neutral i.e. number of positive charges are equal to number of negative charges.

8 0
3 years ago
The car transports 180 m in 12 s. Calculate its speed and express it in m / s and in km / h
makkiz [27]

Explanation:

Given parameters:

Distance  = 180m

Time  = 12s

Unknown:

Speed  in m/s and km/hr

Solution:

Speed is the distance divided by the time taken,

   Speed  = \frac{distance}{time}  

So;

     Speed  = \frac{180}{12}   = 15m/s

   1000m = 1km

  3600s  = 1hr

Therefore;

   15 x m x \frac{1}{s}  x \frac{1km}{1000m} x \frac{3600s}{1hr}    = 54km/hr

5 0
3 years ago
A spring has a spring constant of 55 N/m. How much energy is stored in the spring when it is compressed 0.3 m past it's natural
mixer [17]
E = 0.5kx² = 0.5 * 55 * 0.3² = 2.475
6 0
3 years ago
Read 2 more answers
A sealed 26-m3 tank is filled with 6000 moles of oxygen gas (O2) at an initial temperature of 270 K. The gas is heated to a fina
TiliK225 [7]

Answer:

The final pressure of oxygen gas is 8.33 atm.

Explanation:

From the given data

V=26 m^3 or 26000 L

T1=270K

T2=440K

n1=6000 moles

R=0.0821 L.atm/molK

Now from the ideal gas equation

P_2V_2=nRT_2\\P_2=\frac{nRT_2}{V_2}\\P_2=\frac{6000*0.0821*440}{26000}\\\\P_2=8.33 atm\\

As the options given are not defined in which unit thus the final pressure of oxygen gas is 8.33 atm.

<em>*The options are provided for a different question where </em>

3 0
4 years ago
A spaceship accelerates uniformly for 1220km how much time is needed for the spaceship to increase its speed from 11.1km/s to 11
snow_lady [41]

The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s is 107 s

<h3>Data obtained from the question</h3>

The following data were obtained from the question given above:

  • Initial velocity (u) = 11.1 Km/s
  • Final velocity (v) = 11.7 Km/s
  • Distance (s) = 1220 Km
  • Time (t) =?

<h3>How to determine the time</h3>

The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s can be obtained as illustrated below:

s = (u + v)t / 2

Cross multiply

(u + v)t = 2s

Divide both sides by (u + v)

t = 2s / (u + v)t

t = (2 × 1220) / (11.1 + 11.7)

t = 2440 / 22.8

t = 107 s

Thus, the time taken for the spaceship to change its speed is 107 s

Learn more about speed:

brainly.com/question/680492

Learn more about velocity:

brainly.com/question/3411682

#SPJ1

6 0
2 years ago
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