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Sedbober [7]
4 years ago
10

A sealed 26-m3 tank is filled with 6000 moles of oxygen gas (O2) at an initial temperature of 270 K. The gas is heated to a fina

l temperature of 440 K. The ATOMIC mass of oxygen is 16.0 g/mol, and the ideal gas constant is R = 8.314 J/mol·K = 0.0821 L·atm/mol·K. The final pressure of the gas is closest to
A) 0.31
B) 0.34
C) 0.33
D) 0.36
E) 0.29
Physics
1 answer:
TiliK225 [7]4 years ago
3 0

Answer:

The final pressure of oxygen gas is 8.33 atm.

Explanation:

From the given data

V=26 m^3 or 26000 L

T1=270K

T2=440K

n1=6000 moles

R=0.0821 L.atm/molK

Now from the ideal gas equation

P_2V_2=nRT_2\\P_2=\frac{nRT_2}{V_2}\\P_2=\frac{6000*0.0821*440}{26000}\\\\P_2=8.33 atm\\

As the options given are not defined in which unit thus the final pressure of oxygen gas is 8.33 atm.

<em>*The options are provided for a different question where </em>

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