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3 years ago

In which of the following cases would sound reach each ear out of phase?

Physics

1 answer:

notsponge [240]3 years ago

8 0

Answer:

Explanation:

Because when you stand directly near the source of sound the distance is less and sound is directly proportional to area.

You might be interested in

What times what equals 400

Radda [10]

If you're willing to consider fractions or decimals,
then there are an infinite number of answers.
Like (2.5 x 160), and (15 x 26-2/3).

If you want to stick to only whole numbers,
then these 8 combinations do:

1, 400
2, 200
4, 100
5, 80
8, 50
10, 40
16, 25
20, 20

7 0

4 years ago

The most recently discovered system close to Earth is a pair of brown dwarfs known as Luhman 16. It has a distance of 6.5 light-

just olya [345]

Answer:

1.99 parsecs.

Explanation:

We have been given that the most recently discovered system close to Earth is a pair of brown dwarfs known as Luhman 16. It has a distance of 6.5 light-years.

We know that one light year equals to 0.306601 parsecs. To convert 6.5 light-years to parsecs, we will multiply 0.306601 by 6.5.

$6.5\text{ Light-years}=6.5\times 0.306601\text{ Parsecs}$

$6.5\text{ Light-years}=1.9929065\text{ Parsecs}$

$6.5\text{ Light-years}\approx 1.99\text{ Parsecs}$

Therefore, Luhman 16 is approximately 1.99 parsecs away from the Earth.

5 0

3 years ago

A mass of 4kg suspended by a light string 2m long and at rest is projected horizontally with a velocity of 1.5 m/s. find the ang

Dafna11 [192]

Answer:

19.5°

Explanation:

The energy of the mass must be conserved. The energy is given by:

1) $E=\frac{1}{2}mv^2+mgh$

where m is the mass, v is the velocity and h is the hight of the mass.

Let the height at the lowest point of the be h=0, the energy of the mass will be:

2) $E=\frac{1}{2}mv^2$

The energy when the mass comes to a stop will be:

3) $E=mgh$

Setting equations 2 and 3 equal and solving for height h will give:

4) $h=\frac{v^2}{2g}$

The angle ∅ of the string with the vertical with the mass at the highest point will be given by:

5) $cos\phi=\frac{l-h}{l}$

where l is the lenght of the string.

Combining equations 4 and 5 and solving for ∅:

6) $\phi={cos}^{-1}(\frac{l-h}{l})={cos}^{-1}(1-\frac{h}{l})={cos}^{-1}(1-\frac{v^2}{2gl})$

8 0

4 years ago

Calculate the de Broglie wavelength of an electron traveling at 2.0 x 10^8 m/s (me = 9.1*10^-31 kg).

timofeeve [1]

Answer:

$\lambda=3.64\times 10^{-12}\ m$

Explanation:

We have,

Speed of an electron is $2\times 10^8\ m/s$

It is required to find the De Broglie wavelength of electron. The formula for the De- Broglie wavelength is given by :

$\lambda=\dfrac{h}{mv}$

h is Planck's constant

m is mass of an electron

Plugging all the values we get :

$\lambda=\dfrac{6.63\times 10^{-34}}{9.1\times 10^{-31}\times 2\times 10^{8}}\\\\\lambda=3.64\times 10^{-12}\ m$

So, the De-Broglie wavelength of an electron is $3.64\times 10^{-12}\ m$

4 0

3 years ago

If there is "waste" energy, does the Law of Conservation of Energy still apply? please don't type something random if so i'll ju

FinnZ [79.3K]

Explanation:

Yes, the law of conservation of energy still applies even if there is waste energy.

The waste energy are the transformation products of energy from one form to another.

According to the law of conservation of energy "energy is neither created nor destroyed by transformed from one form to another in a system".

But of then times, energy is lost as heat or sound within a system.

If we take into account these waste energy, we can see that energy is indeed conserved.
The sum total of the energy generated and those produced will be the same if we factor in other forms in which the energy has been transformed into.

8 0

3 years ago